Question

In ΔOPQ, q = 83 inches, p = 80 inches and ∠P=70°. Find all possible values of ∠Q, to the nearest degree

Answer 1

Answer:

77.12°

Step-by-step explanation:

Given that:

In triangle OPQ

∠P=70°

line q = 83 inches

line p = 80 inches

To find ∠Q; we use the since rule:

$\dfrac{Sin \ Q}{q} = \dfrac{Sin \ P}{p}$

$\dfrac{Sin \ Q}{83} = \dfrac{Sin \ 70}{80}$

$Sin \ Q= \dfrac{Sin \ 70 \times 83}{80}$

$\text{Sin \ Q= 0.9749}$

$Q=Sin ^{-1}( 0.9749)$

$\mathbf{Q = 77.12^0}$