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mel-nik [20]
3 years ago
9

In ΔOPQ, q = 83 inches, p = 80 inches and ∠P=70°. Find all possible values of ∠Q, to the nearest degree

Mathematics
1 answer:
dsp733 years ago
3 0

Answer:

77.12°

Step-by-step explanation:

Given that:

In triangle OPQ

∠P=70°

line q = 83 inches

line p = 80 inches

To find ∠Q; we use the since rule:

\dfrac{Sin \ Q}{q} = \dfrac{Sin \ P}{p}

\dfrac{Sin \ Q}{83} = \dfrac{Sin \ 70}{80}

Sin \ Q= \dfrac{Sin \ 70 \times 83}{80}

\text{Sin \ Q= 0.9749}

Q=Sin ^{-1}( 0.9749)

\mathbf{Q = 77.12^0}

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