Question

What are the x-intercepts of the graph of the function f(x)=x2+ 4x-12

Answer 1

x^2 + 4x-12 =0

factor

(x+6) (x-2)=0

x+6=0  x-2=0

x=-6  x=2

are the x intercepts

Answer -6, 2

Answer 2

Answer:

The points are (-6,0) and (2, 0)

Step-by-step explanation:

Given the function f(x)

$f(x)=x^2+ 4x-12$

we have to find the x-intercepts of the graph of function.

x-intercepts are the x-coordinate of a point where a graph of function intersects the x-axis i.e the value of x at which the value of y is 0.

Hence, to find x-intercept we have to put the value of y=0 in f(x)

$x^2+ 4x-12=0$

By middle term splitting method

$x^2-2x+6x-12=0$

Taking x common from first two terms and 6 from last two terms

$x(x-2)+6(x-2)=0$

$(x+6)(x-2)=0$

Using zero product property

⇒ $(x+6)=0\text{ or }(x-2)=0$

$x=-6\text{ or }x=2$

The points are (-6,0) and (2, 0)