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3 years ago

15

Write the quadratic equation in standard form -8x+3x^2=-18

1 answer:

stepladder [879]3 years ago

6 0

X = ± √<span>6 </span><span>= ± 2.4495 because i know it</span>

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Which relation is a function?

Veseljchak [2.6K]

Answer: B

Step-by-step explanation:

because in A it says 2=3 and 2=2 that is not a function each number has to have an outcome of one possible answer if that is true it is a function.

7 0

3 years ago

I NEED HELP ASAP I WILL MARK YOU THE BRAINLIEST

Nataliya [291]

Alternate Interior Angles. You’re welcome

7 0

2 years ago

In the figure shown to the right, two angle measurements are given. Determine the others.

creativ13 [48]

The figure is shown below

From the figure

Angle 150 degree and angle p forms angles on a straight

Since the sum of angles on a straight line equals 180 degrees

Hence

$150^{\circ}+p=180^{\circ}$

Solve for p in the equation

$\begin{gathered} p=180^{\circ}-150^{\circ} \\ p=30^{\circ} \end{gathered}$

Hence, p = 30

From the figure

Angle p and angle q are vertically opposite angles

Since vertically opposite angles are equal then

$p=q=30^{\circ}$

Hence, q = 30

Applying the rule of angles on a straight line

This implies

$q+w+60=180$

Substitute q = 30 into the equation

$30+w+60=180$

Solve for w

$\begin{gathered} w+90=180 \\ w=180-90 \\ w=90 \end{gathered}$

Hence, w = 90

8 0

1 year ago

Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i

sp2606 [1]

i. The Lagrangian is

$L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)$

with critical points whenever

$L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4$

$L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_\lambda=4x^2+y^2-9=0$

If $x=0$ , then $L_\lambda=0\implies y=\pm3$ .
If $y=0$ , then $L_\lambda=0\implies x=\pm\dfrac32$ .
Either value of $\lambda$ found above requires that either $x=0$ or $y=0$ , so we get the same critical points as in the previous two cases.

We have $f(0,-3)=9$ , $f(0,3)=9$ , $f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25$ , and $f\left(\dfrac32,0\right)=\dfrac{729}4$ , so $f$ has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

$L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)$

with critical points whenever

$L_x=2\lambda x=0\implies x=0$ (because we assume $\lambda\neq0$ )

$L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda$

$L_\lambda=x^2+y^2+z^2-36=0$

If $x=y=0$ , then $L_\lambda=0\implies z=\pm6$ .
If $\lambda=-1$ , then $z=-5$ , and with $x=0$ we have $L_\lambda=0\implies y=\pm\sqrt{11}$ .

We have $f(0,0,-6)=60$ , $f(0,0,6)=-60$ , $f(0,-\sqrt{11},-5)=61$ , and $f(0,\sqrt{11},-5)=61$ . So $f$ has a maximum value of 61 and a minimum value of -60.

5 0

3 years ago

What is the value of c?<br> 14 = - 2c - 6 - 3c

Neporo4naja [7]

Answer:

c = -4

Step-by-step explanation:

Step 1: Write equation

14 = -2c - 6 - 3c

Step 2: Solve for <em>c</em>

Combine like terms: 14 = -5c - 6
Add 6 on both sides: 20 = -5c
Divide both sides by -5: c = -4

Step 3: Check

<em>Plug in c to verify it's a solution.</em>

14 = -2(-4) - 6 - 3(-4)

14 = 8 - 6 + 12

14 = 2 + 12

14 = 14

8 0

3 years ago

Read 2 more answers