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alekssr [168]
3 years ago
14

Area question..........

Mathematics
1 answer:
OverLord2011 [107]3 years ago
4 0
Well in area you multiply and perimeter you add, so right now you are multiplying the measures of the triangle, So you can either write out the problem and solve it or use a calculator to get you answer, but I would say to solve it because you never if the calculator could be wrong, so if you wanna write it out then you write 9 then put the 14 under it and put the 5 under 14 but under the 4 of 14, so basically you are just going to multiply 9 by 14 to get 126 then multiply 126 by 5 to get 630, so now 630 is your final answer
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Help me with 16,17,18,and 19 please simpl
mixas84 [53]

Answer:

Ques 16)

We have to simplify the expression:

\dfrac{t^2}{t^2+3t-18}-(\dfrac{5t}{t^2+3t-18}-\dfrac{t-3}{t^2+3t-18})\\   \\=\dfrac{t^2}{t^2+3t-18}-(\dfrac{4t+3}{t^2+3t-18})\\  \\=\dfrac{t^2-4t-3}{t^2+3t+18}

Ques 17)

\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\  \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}

Ques 18)

Let the blank space be denoted by the quantity 'x'.

\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2

Ques 19)

Let the missing quantity be denoted by 'x'.

\dfrac{p^2+7p+2}{p^2+5p-14}-\dfrac{x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\ \\\dfrac{p^2+7p+2-x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\\\\dfrac{p^2+7p+2-x}{(p-2)(p+7)}=\dfrac{p-1}{p-2}\\\\p^2+7p+2-x=(p-1)(p+7)\\\\p^2+7p+2-x=p^2+6p-7\\\\x=p+9


7 0
2 years ago
Kate has a kite with the dimensions shown below. What is the value of X?
sergij07 [2.7K]
Hey there! :D

We will use the properties of similar triangles to figure this out. 

We will use two triangles inside the kite, with sides with the value of "x". 

Smaller triangle:

Smaller side= 11

Bottom side= x

Bigger triangle:

Smaller side= x

Bottom side= 25

\frac{11}{x} = \frac{x}{25}

Cross multiply. 

25*11= 275

x*x= x^{2}

Find the square root. 

√275= 16.583.... 

Or 5√11. 

I hope this helps!
~kaikers

6 0
3 years ago
564 which statement is false? It is the sum of 56 tens and 4 ones. The number of hundreds is more than the number of tens. To ge
nirvana33 [79]

Answer:

The number of hundreds is more than the number of tens.

Step-by-step explanation:

The sum of 56 tens and 4 ones= 560 + 4 (true)

The number of hundreds is more than the number of tens.

Number of hundreds = 5

Number of tens = 56

5 is not greater than 56.

7 0
3 years ago
If l || m, classify the marked angle pair and give their relationship, then solve for X.
pickupchik [31]
Alternate exterior angles(AEA).
Given their relationship the angles are congruent.
8x-71=5x+7
3x-71=7
3x=78
X=26
6 0
2 years ago
A spherical hot air balloon has a diameter of 55 feet when the balloon is inflated the radius increases at a rate of 1.5 feet pe
Nuetrik [128]

Answer: 46.90mins

Step-by-step explanation:

The given data:

The diameter of the balloon = 55 feet

The rate of increase of the radius of the balloon when inflated = 1.5 feet/min.

Solution:

dr/dt = 1.5 feet per minute = 1.5 ft/min

V = 4/3·π·r³

The maximum volume of the balloon

= 4/3 × 3.14 × 55³

= 696556.67 ft³

When the volume 2/3 the maximum volume

= 2/3 × 696556.67 ft³

= 464371.11 ft³

The radius, r₂ at the point is

= 4/3·π·r₂³

= 464371.11 ft³

r₂³ = 464371.11 ft³ × 3/4

= 348278.33 ft³

348278.333333

r₂ = ∛(348278.33 ft³) ≈ 70.36 ft

The time for the radius to increase to the above length = Length/(Rate of increase of length of the radius)

The time for the radius to increase to the

above length

Time taken for the radius to increase the length.

= is 70.369 ft/(1.5 ft/min)

= 46.90 minutes

46.90mins is the time taken to inflate the balloon.

5 0
2 years ago
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