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2 years ago

What are the solutions of the inequality? graph and check the solutions.

Mathematics

1 answer:

sattari [20]2 years ago

6 0

Answer:

Option 3: $x \ge 8$

Graph C

Step-by-step explanation:

Find the solution of $-\frac{x}{4} \le 2$

$-\frac{x}{4} \le 2$

$-x \le 8$ (multiplication property of equality)

Divide both sides by -1. Since we are dividing by a negative number, the sign would change

$x \ge 8$

This means that the possible values of x are 8 and any number above 8.

Graphing this, the arrow of directed line would start at 8 and move towards our right hand.

Thus, the graph would be graph C in option C.

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What is the solution for this inequality? 3(x-4)>5(x-2)-8

Marizza181 [45]

$3x - 12 > 5x - 10 - 8 \\ 10 + 8 - 12 > 5x - 3x \\ 6 > 2x \\ x < 3$

7 0

3 years ago

For what value of a is (a,9) a solution for the equation y=2x+1?

Ivahew [28]

Answer:

Step-by-step explanation:

(a,9).......we dont know " a " (or x) but we do know y...it is 9

so sub in 9 for y and solve for x

y = 2x + 1

9 = 2x + 1

9 - 1 = 2x

8 = 2x

8/2 = x

4 = x <======= ur answer is D

5 0

3 years ago

Find the distance from the point (1,4) to the line y = 1/3x - 3

Troyanec [42]

Answer:

Step-by-step explanation:

If I'm not mistaken, and I very well could be, this is a calculus problem(?). In order to find the distance without calculus you'd need a point on the given line to use to find the distance in the distance formula. But you don't have a point on the given line, so we can find the shortest distance between the point (1, 4) and the given line using the derivative of the polynomial formed when using the distance formula.

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ and we have the x and y for x2 (or x1...it doesn't matter which you choose to fill in):

$d=\sqrt{(1-x)^2+(4-y)^2}$

but what we find is that we have too many unknowns here, namely, the distance, the x coordinate, and the y coordinate. So we can replace the y coordinate with what y is equal to in terms of the linear equation:

$d=\sqrt{(1-x)^2+(4-\frac{1}{3}x-3)^2 }$ and simplify:

$d=\sqrt{(1-x)^2+(7-\frac{1}{3}x)^2 }$

. No we'll expand each binomial by squaring:

$d=\sqrt{(1-2x+x^2)+(49-\frac{14}{3}x+\frac{1}{9}x^2) }$

. Combining like terms gives us

$d=\sqrt{\frac{10}{9}x^2-\frac{20}{3}x+50 }$

The distance between the point (1, 4) and the given line will be at a minimum when the polynomial above is at a minimum. We find the value of x for which the polynomial is at a minimum by finding its derivative, setting the derivative equal to 0, and then solving for x. The derivative of the polynomial is

$\frac{20}{9}x-\frac{20}{3}$

Setting equal to 0 and getting rid of the denominators gives us

20x - 60 = 0

Solving for x gives us

20x = 60 and x = 3.

That's the value of x that gives us the shortest distance between (1, 4) and the line y = 1/3x - 3. Sub into the distance formula that x value to find the distance:

$d=\sqrt{(\frac{10}{9})(3)^2-(\frac{20}{3})(3)+50 }$

which simplifies down, finally, to

x ≈ 6.325 units

8 0

3 years ago

Helpppppp guyssss pleaseeeeeee I’m losttt

Nimfa-mama [501]

Answer:

Step-by-step explanation:

Use definition of conditional probability:

$P(A|B)=\dfrac{P(A\cap B)}{P(B)},$

where

A = the student is a freshman,

B = the student is a male

From the table,

$P(B)=\dfrac{4+6+2+2}{4+6+2+2+3+4+6+3}=\dfrac{14}{30}=\dfrac{7}{15}\\ \\P(A\cap B)=\dfrac{4}{4+6+2+2+3+4+6+3}=\dfrac{4}{30}=\dfrac{2}{15}$

So,

$P(A|B)=\dfrac{\frac{2}{15}}{\frac{7}{15}}=\dfrac{2}{7}\approx 0.29=29\%$

3 0

3 years ago

The brand manager for a brand toothpaste must plan a campaign designed to increase brand recognition. He wants to first determin

bulgar [2K]

We need to find out how many adults must the brand manager survey in order to be 90% confident that his estimate is within five percentage points of the true population percentage.

From the given data we know that our confidence level is 90%. From Standard Normal Table we know that the critical level at 90% confidence level is 1.645. In other words, $Z_{Critical}=1.645$ .

We also know that E=5% or E=0.05

Also, since, $\hat{p}$ is not given, we will assume that $\hat{p}$ =0.5. This is because, the formula that we use will have $\hat{p}(1-\hat{p})$ in the expression and that will be maximum only when $\hat{p}$ =0.5. (For any other value of $\hat{p}$ , we will get a value less than 0.25. For example if, $\hat{p}$ is 0.4, then $1-\hat{p}=0.6$ and thus, $\hat{p}(1-\hat{p})=0.24$ .).