Given:
ΔT = 38 - 26 = 12°C, temperature change
Q = 11.3 J, heat input
c = 0.128 J/(g-°C), specific heat of lead
Let m = the mass of the lead.
Then
Q = m*c*ΔT
(m g)*(0.128 J/(g-°C))*(12 °C) = 11.3 J
1.536m = 11.3
m = 7.357 g
Answer: 7.36 g (2 sig. figs)
Answer:
gravity
Explanation:
We use gravity to do different force.
Answer:
The velocity of the one thrown up will be the same as the second one
Explanation:
They will fall and hit the ground at the same time although they have the same velocity because object one although has double height it has initial velocity of zero
