Answer:
speed of flow of blood in the blocked portion of the vessel is 9.18 vo
Explanation:
given data
diameter of the vessel = 67.0 %
to find out
what is its speed v expressed as a multiple of vo
solution
we know here that Plaque decreases diameter of the vessel by 67%
s here diameter in the blocked portion = 33% of diameter in unblocked portion so
we will apply here Continuity equation that is express as
Ao×Vo = A1×V1 ...................1
here Ao is Cross-sectional area of the cylindrical blood vessel that is =
and do is Diameter of the cylindrical blood vessel and vo is Speed of flow of blood in the blood vessel
and d1 is diameter of the vessel in the blocked portion of the vessel that is = 0.33 do and A1 is cross section area of the vessel in the blocked portion that is = and v1 is Speed of flow of blood in the blocked portion of the vessel
so now we put value in equation 1 we get
Ao×Vo = A1×V1
× vo = × v1
do²×vo = d1²×v1
do²×vo = d1²×v1
do²×vo = (0.33 do)²×v1
solve it we get
v1 = 9.18 vo
so speed of flow of blood in the blocked portion of the vessel is 9.18 vo
I think it is B I hope it is correct
h=5t^2
Replace what you know making the equation
h=5(4)^2
now get ride of 4^2
4^2=16
h=5(16)
now multiply 5 and 16
resulting in the answer
H=80
To develop this problem we will apply the concepts related to Sound Intensity. This can be defined as the power carried by sound waves per unit area in a direction perpendicular to that area. Mathematically it can be written as,
= Level Difference
n = Number of equal loud sound sources
n = 15
Therefore replacing we have,
Therefore over 100dB the total difference intensity level would be
Here,
The intensity level generated by one engine is
D. The chemical potential energy of real battery decreases, it develops internal resistance and therefore the potential difference across its terminals decreases if its current increases.