We can use the kinematic equation

where Vf is what we are looking for
Vi is 0 since we start from rest
a is acceleration
and d is the distance
we get
(Vf)^2 = (0)^2 + 2*(2)*(500)
(Vf)^2 = 2000
Vf = about 44.721
or 44.7 m/s [if you are rounding this by significant figures]
The wavelength of the h-alpha absorption line that you would detect in the star's spectrum will be 54.67 *
nm
If the object is moving towards or away from us with some radial velocity, shifts can be observed in the location of the absorption
since, material is moving towards us a shift to shorter wavelength will be observed
shift = rest wavelength * ( radial velocity / speed of light )
= 656 *
* (250 *
/ 3 *
)
= 54.67 *
nm
The wavelength of the h-alpha absorption line that you would detect in the star's spectrum will be 54.67 *
nm
learn more about radial velocity:
brainly.com/question/22409504?referrer=searchResults
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<span>C. surface tension of the water.</span>
Answer:
The angular distance in revolution is 
The angular distance in radians is 
The angular distance in degrees is 
The angular size is 
Explanation:
From the question we are told that
The diameter is 
The distance moved by the rim is 
Generally the circumference of the pie plate is mathematically represented as

Substituting the values


The number resolution carried out by the pie plate is evaluated as

Substituting value


The angular distance
is mathematically evaluated as

Where r is the radius which is mathematically evaluated as

Substituting this into the equation for angular distance


The angular distance traveled in degrees is


When the pie is cut into 9 equal parts
The angular size would be mathematically evaluated as


Answer:
Explanation:
Charge on uranium ion = charge of a single electron
= 1.6 x 10⁻¹⁹ C
charge on doubly ionised iron atom = charge of 2 electron
= 2 x 1.6 x 10⁻¹⁹ C = 3.2 x 10⁻¹⁹ C
Let the required distance from uranium ion be d .
force on electron at distance d from uranium ion
= 9 x 10⁹ x 1.6 x 10⁻¹⁹ / r²
force on electron at distance 61.10 x 10⁻⁹ - r from iron ion
= 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²
For equilibrium ,
9 x 10⁹ x 1.6 x 10⁻¹⁹ / r² = 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²
2 d² = (61.10 x 10⁻⁹ - r )²
1.414 r = 61.10 x 10⁻⁹ - r
2.414 r = 61.10 x 10⁻⁹
r = 25.31 nm .