A student at the top of a building of height h throws one ball upward with a speed of vi and then throws a second ball downward
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Answer: The time of contact will be 0.006 seconds.
Explanation:
An impulse of a force is the product of average force and the time interval when the force acts.
Mathematically,
Where,
J = impulse = 3.6 Ns
F = Force = 600N
= Time = ?s
Putting the values in above equation, we get:
t = 0.006 seconds
Hence, the time of contact will be 0.006 seconds.