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Alinara [238K]
2 years ago
6

Which one you think is the right one? (No link pls)

Mathematics
1 answer:
Montano1993 [528]2 years ago
5 0

Answer:

You are correct, it is B.

Step-by-step explanation:

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What’s this in standard form
AlladinOne [14]

Answer:

0.614

Step-by-step explanation:

4 0
2 years ago
Solve the inequality 2x>30+5/4x
insens350 [35]

Answer:

Step-by-step explanation:

2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} }  \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0

x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }

case~2

if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0

8 0
1 year ago
Find the height of the triangle.
Ierofanga [76]

Answer:

The value of x = 3.42

Step-by-step explanation:

Formula:

Sin ∅ = Opposite side /Hypotenuse

From the figure we can see a right angled triangle.

One angle is given, hypotenuse = 10 and height = x.

To find the value of x

sin 20 = Opposite side/hypotenuse = x/10

x = 10 * sin 20

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Therefore the value of x = 3.42

7 0
3 years ago
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What is 9 over 5 in a percent
Nataly_w [17]
So you convert the fraction into a decimal then multiply it by 100 so the percentage would be 180%
3 0
3 years ago
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The volume of a​ cone-shaped hole is 50 pi ft cubed . If the hole is 6 ft​ deep, what is the radius of the​ hole?
True [87]

Answer:

r = 5

Step-by-step explanation:

The formula for volume of a cone is \pi r^2*\frac{h}{3}

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r = 5

8 0
3 years ago
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