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Genrish500 [490]
3 years ago
12

List all subsets of the set S = {a,b}

Mathematics
1 answer:
pickupchik [31]3 years ago
8 0

{}  {A} {B} {A, B} are the subsets

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Find<br>a,b<br>such<br>that 7.2, a, b, 3 are in A.P.​
leonid [27]

Answer:

  • The value of a = 5.8
  • The value of b = 4.4

Step-by-step explanation:

Given

7.2, a, b, 3 are in A.P

2a = 7.2+b

b = 2a - 7.2

as

a, b, 3 are also in A.P

2b\:=\:a\:+\:3

Putting b = 2a - 7.2

2\left(2a-7.2\right)=a+3

4a-14.4=a+3

\mathrm{Add\:}14.4\mathrm{\:to\:both\:sides}

4a-14.4+14.4=a+3+14.4

4a=a+17.4

4a-a=a+17.4-a

3a=17.4

\mathrm{Divide\:both\:sides\:by\:}3

\frac{3a}{3}=\frac{17.4}{3}

a=5.8

Now, plugging a=5.8 in b = 2a - 7.2

b=2\left(5.8\right)-7.2

b=2\cdot \:5.8-7.2

b=11.6-7.2

b=4.4

Therefore,

  • The value of a = 5.8
  • The value of b = 4.4
4 0
3 years ago
the second term of a geometric sequence is 18 and the fourth term is 8 find the common ratio . And find the sum of the first 6 t
777dan777 [17]

Answer:

  • ratio: 2/3
  • sum: 73 8/9

Step-by-step explanation:

The general term of a geometric sequence is ...

  an = a1·r^(n-1)

You have the 2nd and 4th terms, so ...

  a2 = a1·r^(2-1) = a1·r

  a4 = a1·r^(4-1) = a1·r^3

We can find r from the ratio ...

  a4/a2 = (a1·r^3)/(a1·r) = r^2 = 8/18 = 4/9

Then r is ...

  r = √(4/9) = 2/3 . . . . the common ratio

The first term is ...

  a2 = 18 = a1·(2/3)

  a1 = (3/2)·18 = 27

__

The sum of the first 6 terms is ...

  Sn = a1·(r^n -1)/(r -1)

  S6 = 27·((2/3)^6 -1)/(2/3 -1)

  S6 = 27·(64/729-1)/(2/3-1) = (27)(665)/243 = 73 8/9

The sum of the first 6 terms is 73 8/9.

_____

<em>Check on the sum</em>

The first 6 terms are ...

  27, 18, 12, 8, 5 1/3, 3 5/9

Their sum is 73 8/9, as above.

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The probability is 1/3
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 i belive 60% becuse it lands on heads 60 time out of a hudred 
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Answer:

A

Step-by-step explanation:

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