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Leno4ka [110]
3 years ago
5

For each gym membership sold, the gym keeps $42 and the employee who sold it gets $8. What is the commission the employee earned

as a percentage of the total cost of the gym me
Mathematics
2 answers:
horrorfan [7]3 years ago
4 0

Answer:

Commission of the employee = 16%

Step-by-step explanation:

It is given that:

Amount kept by gym = $42

Amount given to employee = $8

Total fee = 42 + 8 = $50

Commission rate = \frac{Commission}{Total\ fee}*100

Commission rate = \frac{8}{50}*100

Commission rate = 0.16 * 100 = 16%

Therefore,

Commission of the employee = 16%

Basile [38]3 years ago
4 0

Answer:

Yeah I'm pretty much just clarification that it's 16% if anyone was wondering ;-; I don't really have much purpose here

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Answer:

134 degrees.

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This is a simple one.

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So the measure of the arc RS is 2 * 67 = 134 degrees.

3 0
3 years ago
Is 9.058 greater than less than or equal to 9.24<br>​
Crank

Answer:

9.058 is less than 9.24

Step-by-step explanation:

there is 0 in the tenth digit and there is 2 in the tenths digit so therefor, 9.058 is less than 9.24

Hope this helps:)

3 0
3 years ago
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In a survey, 200 people were polled about whether they preferred spending their free time playing sports, watching a movie, or r
Rama09 [41]
A) 25% of males preferred playing sports.

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B) 25% of the people surveyed preferred reading a book.

Explanation) You have to add up how many males and females rather
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8 0
3 years ago
The sum of two numbers is 85. If four times the smaller number is subtracted from the larger number, the result is 5. Find the t
Cerrena [4.2K]

Answer:

the larger number is 69

the smaller number is 16

Step-by-step explanation:

x is the smaller number

y is the larger number

x + y = 85

y - 4x = 5

y = 5 + 4x

x + 5 + 4x = 85

5x = 80

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5 0
3 years ago
Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the pro
umka21 [38]

|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%

8 0
3 years ago
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