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ioda
3 years ago
11

1. Which set of side lengths form a right triangle?

Mathematics
1 answer:
Greeley [361]3 years ago
5 0

Answer:

7,8,9

Step-by-step explanation:

Even though it can be be 7,24,25

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The temperature one morning in Shasta was LaTeX: -12^\circ F− 12 ∘ F. By the afternoon, the temperature had risen LaTeX: 8^\circ
Vlad [161]

Answer:

The Temperature in the afternoon was -4\° F.

Step-by-step explanation:

Given:

Temperature in the morning = -12\° F

Rise in temperature = 8\° F

We need to find the temperature in the afternoon.

Solution:

Now we know that;

temperature in the afternoon is equal to Temperature in the morning plus Rise in temperature in afternoon.

framing in equation form we get;

temperature in the afternoon = -12\° F+8\° F=-4\° F

Hence the Temperature in the afternoon was -4\° F.

3 0
3 years ago
WILL MARK BRAINLIEST!
Maurinko [17]

Answer:

  A)  square; rectangle; rhombus

Step-by-step explanation:

Opposite sides are parallel and all sides are the same length. Angles at the corners are 90°, so the figure is a rhombus, rectangle, and square: choice A.

7 0
3 years ago
I need help with this who can help me
Elena L [17]
What’s do you need help on
7 0
3 years ago
A= 1/2bh, for b
andrew11 [14]
Work backwards until b is by itself.
1. multiply 2 by both sides: 2A=bh
2.divide h by both sides: 2A/h = b
6 0
3 years ago
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(2^8 x 3^−5 x 6^0)−2 x 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 x 2^28
Veronika [31]

(2^8\cdot3^{-5}\cdot6^0)^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot2^{28}\\\\=(2^8)^{-2}\cdot(3^{-5})^{-2}\cdot1^{-2}\cdot\dfrac{(3^{-2})^4}{(2^3)^4}\cdot2^{28}\\\\=2^{-16}\cdot3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot2^{28}\\\\=2^{-16}\cdot2^{28}\cdot2^{-12}\cdot3^{10}\cdot3^{-8}\\\\=2^{-16+28+(-12)}\cdot3^{10+(-8)}\\\\=2^0\cdot3^2=1\cdot9=\boxed{9}\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}

4 0
4 years ago
Read 2 more answers
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