Plsss help me thanks :D

Which term could be put in the blank to create a fully simplified polynomial written in standard form?

Katena32 [7]

Correct Question:

Which term could be put in the blank to create a fully simplified polynomial written in standard form?

$8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y3$

Options

$x^2y^2$ $x^3y^3$ $7xy^2$ $7x^0y^3$

Answer:

$x^2y^2$

Step-by-step explanation:

Given

$8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3$

Required

Fill in the missing gap

We have that:

$8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3$

From the polynomial, we can see that the power of x starts from 3 and stops at 0 while the power of y is constant.

Hence, the variable of the polynomial is x

This implies that the power of x decreases by 1 in each term.

The missing gap has to its left, a term with x to the power of 3 and to its right, a term with x to the power of 1.

This implies that the blank will be filled with a term that has its power of x to be 2

From the list of given options, only $x^2y^2$ can be used to complete the polynomial.

Hence, the complete polynomial is:

$8x^3y^2 -x^2y^2+ 3xy^2 - 4y3$

4 0

2 years ago

Read 2 more answers

Helppppppp ASAP plsss

zhuklara [117]

If p = 2, insert the value of p.

2^3 = 2 x 2 x 2 = 4 x 2 = 8

so p^3 = 8

6 0

3 years ago

if a coin is tossed 4 times, the odds of it coming up either heads every time or tails every time are 1:7.What is the probabilit

ivanzaharov [21]

Answer:

$1$

Explanation:

From the question, we have it that the probability of heads coming up every time or tail coming up every time is 1:7 if the coin is tossed in 4 tosses

What this means is that we have a probability of 1/8 of head showing up and a probability of 7/8 that a tail will show up in each toss of the coin

For four throws, it means all four are heads or all four are tails

If all four are heads, we have the probability of this happening as:

$\text{ (}\frac{1}{8})^{}$

if all four are tails, we have the probability as:

$\frac{7}{8}$

Now, the probability of either heads or all tails after 4 tosses will be:

$\text{ }\frac{1}{8}\text{ + }\frac{7}{8}\text{ = 1}$

8 0

1 year ago

C+-c=0<br> Identity Property<br> Associative Property<br> Communtative Property<br> Inverse Property

Zanzabum

Answer:

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7 0

2 years ago

For consumers making purchases online, 60% have devices made by Apple, 85% own a smartphone, and 75% use Venmo. Also, out of the

kompoz [17]

Answer:

The probability that a customer selected at random has an Apple device or own a smartphone or both is 0.94

Step-by-step explanation:

The percentage of costumers that have a device made by Apple = 60%

The percentage of customers that own a smartphone = 85%

The percentage of customers that use Venmo = 80%

The percentage out of the smartphone users that use Venmo = 80%

The probability both independent events A and B occurring = P(A) × P(B)

The exclusive probability of A or B occurring P(A XOR B) = P(A) + P(B) - 2 × P(A ∩ B)

Therefore, the probability of A or B or both occurring is given as follows;

P(A or B or Both) = P(A) + P(B) - 2 × P(A ∩ B) + P(A) × P(B)

Where A represent the percentage of costumers that have a device made by Apple and let B represent the percentage of users that have a smartphone, we have;

P(A or B or Both) = 0.6 + 0.85 - 2×0.6×0.85 + 0.6 × 0.85 = 0.94

Therefore, the probability that a customer selected at random has an Apple device or own a smartphone (or both), P(A or B or Both) = 0.94

5 0

3 years ago