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3 years ago

A system of equations is shown.

Mathematics

1 answer:

igomit [66]3 years ago

7 0

Answer:

option c

Step-by-step explanation:

there are no solutions because they are parallel as they have same slope

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A line m is perpendicular to an angle bisector of ∠A. The sides of ∠A intersect this line m at points M and N. Prove that △AMN i

Ray Of Light [21]

Answer:

Step-by-step explanation:

Given: A line m is perpendicular to the angle bisector of ∠A. We call this

intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.

AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.

To Prove: ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are

equal.

Solution: Now, In ΔADM and ΔADN

∠MAD=∠NAD ...(1) (∵Given)

AD=AD ...(2) (∵common side)

∠ADM=∠ADN ...(3) (∵Given)

Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN

( ∵ ASA congruence rule)

⇒ AM=AN

Now, In Δ AMN

AM=AN (∵ Proved)

Hence, ΔAMN is an isosceles triangle.

7 0

3 years ago

Find the value of a2+bc√−d, when a = –3, b = 2, c = 100, and d = –2.

pav-90 [236]

Umm im pretty sure d= -3x im not to sure

5 0

3 years ago

Read 2 more answers

Find tan , sin , and seco, where 0 is the angle shown in the figure.

kicyunya [14]

Answer:

tan(θ) = 5/3
sin(θ) = 5√34/34
sec(θ) = √34/3

Step-by-step explanation:

The hypotenuse is given by the Pythagorean theorem:

h = √(3² +5²) = √34

The trig functions are the ratios of sides:

Tan = Opposite/Adjacent

tan(θ) = 5/3

Sin = Opposite/Hypotenuse

sin(θ) = 5/√34 = (5/34)√34

Sec = Hypotenuse/Adjacent

sec(θ) = √34/3

3 0

3 years ago

The hypotenuse of a 45°-45°-90° triangle measures 22 2 units.

Aleonysh [2.5K]

Answer:

Option C.

Step-by-step explanation:

Given information: The hypotenuse of a 45°-45°-90° triangle measures 22√2 units.

Let x be the length of one leg.

From the given figure it is clear that length of both legs are same.

According to the Pythagoras theorem, in a right angled triangle

$(leg_1)^2+(leg_2)^2=hypotenuse^2$

Substitute $leg_1=leg_2=x, hypotenuse=22\sqrt{2}$ in the above formula.

$(x)^2+(x)^2=(22\sqrt{2})^2$

$2x^2=(22)^2(\sqrt{2})^2$

$2x^2=2(22)^2$

Divide both sides by 2.

$x^2=(22)^2$

Taking square root on both sides.

$x=22$

The length of one leg is 22 units.

Therefore, the correct option is C.

6 0

4 years ago

Read 2 more answers

How to solve 24= -v/3

vredina [299]

24 = -v/3 (first you multiply 3 to each side)
×3 ×3

72 = -v (then you divide -1 from each side)

-72 = v

8 0

4 years ago