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Komok [63]
3 years ago
10

A smokestacks, AB, is 55 m high. From two points C and D on the same side of the smokestack’s base B, the angles of elevation to

the top of the smokestack are 40 degrees and 36 degrees repectively. Find the distance between C and D to the nearest metre.
Plz guys help me with this question ASAP

Show all working

Thank you so much God Bless you brother

Mathematics
1 answer:
Helen [10]3 years ago
8 0

Answer:

CD=10.15m

Step-by-step explanation:

<u>Find the distance of BC.</u>

Tan(40)=55/BC

BC=65.55m

<u>Find the distance of BD.</u>

Tan(36)=55/BD

BD=75.70m

<u>Use BC and BD to find CD</u>

BD-BC=CD

75.70-65.55=CD

CD=10.15m

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