A smokestacks, AB, is 55 m high. From two points C and D on the same side of the smokestack’s base B, the angles of elevation to

Question

2 years ago

10

A smokestacks, AB, is 55 m high. From two points C and D on the same side of the smokestack’s base B, the angles of elevation to

the top of the smokestack are 40 degrees and 36 degrees repectively. Find the distance between C and D to the nearest metre.
Plz guys help me with this question ASAP

Show all working

Thank you so much God Bless you brother

Mathematics

1 answer:

Helen [10] · Answer 1 · 2022-09-18T08:30:10+03:00

Helen [10]2 years ago

8 0

Answer:

CD=10.15m

Step-by-step explanation:

Find the distance of BC.

Tan(40)=55/BC

BC=65.55m

Find the distance of BD.

Tan(36)=55/BD

BD=75.70m

Use BC and BD to find CD

BD-BC=CD

75.70-65.55=CD

CD=10.15m