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3 years ago

What is the volume of the cube below

Mathematics

2 answers:

Crank3 years ago

6 0

Answer: 4x^2

Step-by-step explanation:

Over [174]3 years ago

5 0

Answer:

Option (d) is correct.

The Volume of given cube is 4x²

Step-by-step explanation:

Given : A cube with side 4 , x, and x units

We have to find the volume of the given cube.

Volume of a cube is given as side × side × side

Given side of cube are

4 , x, and x

Thus,

Volume of given cube is = 4 × x × x = 4x²

Thus, Option (d) is correct.

The Volume of given cube is 4x²

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Minchanka [31]

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3 years ago

Does 9+5a=2a+9 have a infinitely many solution?

adelina 88 [10]

Answer:

No it doesn't

Step-by-step explanation:

It doesn't because the numbers are not the same.

4 0

3 years ago

Solve for x^2-2x+1=0

seraphim [82]

Answer:

$x=1$

Step-by-step explanation:

$x^2-2x+1=0\\$

We will start by using the quadratic formula.

$\frac{-(-2)+-\sqrt{(-2)^2-4(1)(1)}}{2(1)}$

We will simplify that and get:

$\frac{-(-2)}{2(1)}$

So our answers would be:

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7 0

2 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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2 years ago

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MAXImum [283]

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6 0

2 years ago