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Vika [28.1K]
2 years ago
11

Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9). (4, -4) (2, -2) (1, -4)

Mathematics
1 answer:
Rus_ich [418]2 years ago
8 0

Answer:

(2,-2)

Step-by-step explanation:

The midpoint of the line segment with endpoints (x_1,y_1) and (x_2,y_2) has coordinates

\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

If the endpoints of the line segment are (-2,5) and (6,-9), then the midpoint has the coordinates

\left(\dfrac{-2+6}{2},\dfrac{5+(-9)}{2}\right)\\ \\\left(\dfrac{4}{2},\dfrac{-4}{2}\right)\\ \\(2,-2)

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Answer:

$125.50

but I'm not sure

Step-by-step explanation:

100÷100=1

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100-12=88

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0.5×25=12.50

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t-shirt with discount = $37.50

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2 years ago
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madam [21]

Answer:

x = y − 6 Is your answer

Step-by-step explanation:

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2 years ago
What is the thirty-second term of the arithmetic sequence -12, -7, -2, 3, ... ? Show your work.
anzhelika [568]

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Further explanation:

As it is already given that the given sequence is an arithmetic sequence

We have to find the common difference first

So,

a_1=-12\\a_2=-7\\a_3=-2\\a_4=3

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The common difference is 5.

And first term is -12

The explicit formula for arithmetic sequence is:

a_n=a_1+(n-1)d\\Here,\\a_n\ is\ nth\ term\\a_1\ is\ first\ term\\d\ is\ common\ difference

Putting the values in the formula

a_n=-12+(n-1)(5)\\a_n=-12+5n-5\\a_n=-17+5n

Putting n=32 in explicit formula

a_{32}=-17+5(32)\\=-17+160\\=143

The thirty-second term is 143

Keywords: Common difference, Arithmetic Sequence

Learn more about arithmetic sequence at:

  • brainly.com/question/10879401
  • brainly.com/question/10940255

#LearnwithBrainly

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Step-by-step explanation:

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Answer:

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