Choose the numerical expression that represents multiplying the sum of 159 and 833 by 6

Someone help me with this plzzz asapp

bazaltina [42]

Answer:

3(25π/2) + 100 = 217.8097

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the equation that going through these points.<br><br>urgent!! will give the brainliest

vampirchik [111]

Answer:

The correct answer is y = -3x + 1.

Step-by-step Explanation:

First, you need to use the point slope formula to determine the slope. This is determined by the formula of the second y-coordinate (the y-coordinate in the second ordered pair) minus the first y-coordinate (the y-coordinate in the first ordered pair).

When subtracting the two values, you receive 7 - -5. You would use the KCC (keep, change, change) rule and keep positive 7, change the minus to addition, and turn negative 5 into positive 5. This gives you a value of 12.

Then, you use the same formula layout for the x-coordinates. Take the x-coordinate in the second ordered pair and subtract the x-coordinate in the first ordered pair to get -2 - 2 = -4.

Finally, to determine the slope, divide 12 and -4 to get -3.

Then, to get the y-intercept placed at the end, you will need to substitute the coordinate values from one of the ordered pairs into the equation y = -3x + b. I chose to use the first ordered pair, so:

-5 = -3(2) + b (Multiply the slope by x to earn the new value)

-5 = -6 + b (Add the -6 to the -5 to isolate the b)

1 = b (b = 1) (Learn that b = 1)

Your final equation will be y = -3x + 1.

8 0

3 years ago

Read 2 more answers

Use the diagram to answer the question.

Aloiza [94]

Answer:

O lines and line t Intersect at Point P

5 0

2 years ago

Is the point (3, 11) a solution for the linear equation 1/3x + y = 12? Explain.

PtichkaEL [24]

9514 1404 393

Answer:

yes

Step-by-step explanation:

The point is on the line.

The coordinate values satisfy the equation:

1/3x + y = 12

1/3(3) + 11 = 12 . . . substitute for x and y

1 + 11 = 12 . . . . . . . true

Any point that satisfies the equation is a solution. (3, 11) is a solution.

5 0

2 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

2 years ago

Choose the numerical expression that represents multiplying the sum of 159 and 833 by 6​

Choose the numerical expression that represents multiplying the sum of 159 and 833 by 6