Answer:
The answer is B.
Step-by-step explanation:
3< x _<5
Quadratic Equations in Single Variable
n²-3n+10=0
2x²+2x+1=0
25b²-16=0
f²-3f+2=0
1/3m +2m=4
a²=225
Linear Equation in single Variable
8-3k=12
5w+5=0
10u-5=8
Linear Equation in Two Variable
2y-z=9
3r+2e=6
d=3e-7
<h3>What is an equation?</h3>
It should be noted that an equation simply means the expression that's used to show the relationship between the variables.
In this case, the equation has been grouped.
Learn more about equations on:
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Group the given equations into two based on observed common properties.
Equations
n²-3n+10=0
8-3k=12
2y-z=9
2x²+2x+1=0
25b²-16=0
3r+2e=6
5w+5=0
f²-3f+2=0
d=3e-7
1/3m +2m=4
10u-5=8
a²=225
let us take any two points here (5,20) and (7,30)
now let us use slope formula to get its slope


slope =5
now let us use one coordinate (say (5,20)) and slope to get the y intercept
20= 5*5 +b
b=-5
plugging the values of b and m in the given equation we get
y=5x-5
or c=5m-5
Hello!
First of all let's find the perimeter (circumference) of the semi circles. We can combine them to make one circle with a diameter of 4 (as we can see the side length of one semi circle is 4 cm. We now plug it into the circumference equation (

=3.14).
4(3.14)=12.56
Now we add up the side lengths of the rectangle.
4+6+4+6=20
Now we add up the length of our circle and rectangle.
20+12.56=32.56
Therefore our answer is
32.56 cm.
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Now to find the area! If we combine the two semicircles, we get a circle with a diameter of four. This means that is has a radius of two. We use the equation below to find the area of the two circles.
A=

r²
First we will square our radius.
2(2)=4
Now we multiply by pi.
4(3.14)=12.56
Now we need to find the area of the rectangle.
6(4)=24
Now we add.
24+12.56=
36.56.
I hope this helps!