2 years ago

A = 2b so what is the value of b-a=?

Mathematics

2 answers:

Dafna11 [192]2 years ago

7 0

Answer:

a=2b

b-a=x

ax=2b²

x=2b²/a

therefore, b-a=2b²/a

irga5000 [103]2 years ago

3 0

Answer:

-b

Step-by-step explanation:

b-a

=b-2b [a=2b]

=-b

note: This is what I think the answer might be but it looks too easy to be correct so i might be wrong:(

You might be interested in

What is the equation of 60km

Ksju [112]

Whats the rest of it

6 0

2 years ago

Arnold puts $580 in a savings the account pays 3% simple interest. how much interest will he earn in 5 years

Mkey [24]

Answer:Arnold earns $87 of interest in 5 years.

Step-by-step explanation:

7 0

3 years ago

Piz help me fast asap thx

Effectus [21]

Answer:

y= 7703.5

Step-by-step explanation:

multiply 7100 by 1.085

5 0

2 years ago

Can someone answer this questions please answer it correctly if it’s correct I will mark you brainliest

muminat

Answer:

Step-by-step explanation:

0.1=1/10

1/10 is just the fraction form of 0.1

3 0

2 years ago

Read 2 more answers

Find the exact value of csc theta if tan theta = sqrt3 and the terminal side of theta is in Quadrant III.

WARRIOR [948]

Answer:

3rd option

Step-by-step explanation:

Using the identities

cot x = $\frac{1}{tanx}$

csc² x = 1 + cot² x

Given

tanθ = $\sqrt{3}$ , then cotθ = $\frac{1}{\sqrt{3} }$

csc²θ = 1 + ( $\frac{1}{\sqrt{3} }$ )² = 1 + $\frac{1}{3}$ = $\frac{4}{3}$

cscθ = ± $\sqrt{\frac{4}{3} }$ = ± $\frac{2}{\sqrt{3} }$

Since θ is in 3rd quadrant, then cscθ < 0

cscθ = - $\frac{2}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = - $\frac{2\sqrt{3} }{3}$

8 0

2 years ago

A = 2b so what is the value of b-a=?​

A = 2b so what is the value of b-a=?