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77julia77 [94]
3 years ago
6

The cost of 1 movie ticket is $7.50. The cost of 2 movie tickets is $15. Based on this constant rate of change, what is the cost

of 4 movie tickets?
Mathematics
1 answer:
Ann [662]3 years ago
7 0

Answer: $30

Step-by-step explanation:

If 2 movie tickets cost $15, you can multiply that by 2 to get the cost of 4 movie tickets.

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Select all the pairs of equivalent expressions.
iren2701 [21]

Answer:

\huge\boxed{(3^4)^4=3^8\cdot3^8}\\\boxed{4^3\cdot5^3=20^3}\\\boxed{(4^3)^3=4^3\cdot4^3\cdo4^3}

Step-by-step explanation:

a^n\cdot a^n=a^{n+m}\\\\(a^n)^m=a^{n\cdot m}\\\\(a\cdot b)^n=a^n\cdot b^n\\=====================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3=4^{3+3}=4^6\\\\4^9\neq4^6\to(4^3)^3\neq4^3\cdot4^3\\==================

(3^4)^4=3^{4\cdot4}=3^{16}\\3^8\cdot3^8=3^{8+8}=3^{16}\\\\(3^4)^4=3^8\cdot3^8\\================

6^4\cdot3^4=(6\cdot3)^4=18^4\\\\18^4\neq18^8\to6^4\cdot3^4\neq18^8\\=================

4^3\cdot5^3=(4\cdot5)^3=20^3\\\\4^3\cdot5^3=20^3\\=================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3\cdot4^3=4^{3+3+3}=4^9\\\\(4^3)^3=4^3\cdot4^3\cdot4^3

3 0
3 years ago
What is the solution to the system of equations? y= -5x + 3 y=1​
Scrat [10]
> y(1) = -5x + 3
-3. -3

> -2 = -5x
÷-5. ÷-5

= 0.4 = x
8 0
3 years ago
helene was paid a total of $33.00 for the 6 hours she worked. she continues to be paid at the same rate. how long would it take
natita [175]

The number of hours that helena need to work to generate 165 dollars is

33 hours.

Helena has to work hours to earn $165. 33

Algebraic equations are equations with

unknown variables. The alphabet letters are used to represent algebraic equations.

Total $33.00 in her 6 hours she worked.

This question should find out how long it takes her to earn her $165.00 in that job.

let x hours be required work hours to earn $165.00 ..

This can be expressed in algebraic equations as:

x= 6× 165/33

x= 990/33

x= 30

Hence, helna have to work thirty hours to earn $165.00 ..

To learn more about Work time problem solving, refer:

brainly.com/question/15447610

#SPJ4

7 0
1 year ago
Use the substitution method to solve the system of equations
yarga [219]

Answer:

C. (3,2)

Step-by-step explanation:

to begin the substitution method, we can begin by substituting the answer choice value into the given system or equations to determine if the values make the equation true.

the first choice is (2,1)

3(2) + 2(1) = 13

6 + 2 is not equal to 13. Therefore this answer choice is incorrect.

second choice (1,2)

3(1) + 2(2) = 13

3 + 4 is not equal to 13. This answer is also incorrect.

third choice (3,2)

3(3) + 2(2)

9 + 4 = 13 is true!

we can also substitute these x and y values for the equation underneath:

y = x - 1

2 = 3 - 1

2 = 2 is true! Therefore, C. (3,2) is correct!

5 0
3 years ago
How do you factorize p2 + 2p - 3 =0
julia-pushkina [17]

Answer:

Solution

p = {-3, 1}

Step-by-step explanation:

Simplifying

p2 + 2p + -3 = 0

Reorder the terms:

-3 + 2p + p2 = 0

Solving

-3 + 2p + p2 = 0

Solving for variable 'p'.

Factor a trinomial.

(-3 + -1p)(1 + -1p) = 0

Subproblem 1

Set the factor '(-3 + -1p)' equal to zero and attempt to solve:

Simplifying

-3 + -1p = 0

Solving

-3 + -1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '3' to each side of the equation.

-3 + 3 + -1p = 0 + 3

Combine like terms: -3 + 3 = 0

0 + -1p = 0 + 3

-1p = 0 + 3

Combine like terms: 0 + 3 = 3

-1p = 3

Divide each side by '-1'.

p = -3

Simplifying

p = -3

Subproblem 2

Set the factor '(1 + -1p)' equal to zero and attempt to solve:

Simplifying

1 + -1p = 0

Solving

1 + -1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + -1 + -1p = 0 + -1

Combine like terms: 1 + -1 = 0

0 + -1p = 0 + -1

-1p = 0 + -1

Combine like terms: 0 + -1 = -1

-1p = -1

Divide each side by '-1'.

p = 1

Simplifying

p = 1

Solution

p = {-3, 1}

4 0
3 years ago
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