Answer:
1 / 5
Step-by-step explanation:
Given that:
Number of white marbles = 5
Number of blue marbles = 3
Number of green marbles = 7
Required is the approximate probability of drawing 2 green marbles, Note that drawing is done without replacement :
Probability = required outcome / Total possible outcomes
Total possible outcomes = sum of all marbles = (5 + 3 + 7) = 15 marbles
First draw:
P(Green) = 7 / 15
Second draw:
Required outcome = 7 - 1 = 6
Possible outcomes = 15 - 1 = 14
P(green) = 6 / 14
Probability of drawing out two green marbles :
(7/15 * 6/14) = 42 / 210 = 1 / 5
Answer:
b(-10) = 6
Step-by-step explanation:
Step 1: Define
b(x) = |x + 4|
b(-10) is x = -10
Step 2: Substitute and Evaluate
b(-10) = |-10 + 4|
b(-10) = |-6|
b(-10) = 6
First, create an equation with the criteria given.
If we let x be your number,
(
is twice the product of 3 and x, and if it exceeds
by 10, then we add 10 to
to make the two sides of the equation equal.)
Now, solve for
.
Hi there!
So if BC and DA are the same, then BA and CD are also the same...
The only one that’s left is BD.
Therefore, the shortest side is BD.
