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2 years ago

If the equation ax+b=cx+d has no solution what must be true about a, b, c, and d?

Mathematics

1 answer:

kykrilka [37]2 years ago

5 0

9514 1404 393

Answer:

a = c
b ≠ d

Step-by-step explanation:

For there to be no solution, the lines represented by the left-side and right-side expressions must be parallel. That is, the coefficients of x must be identical,

a = c

and the y-intercepts must be different:

b ≠ d.

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(m-5)(m-2) simplified

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3 years ago

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3 years ago

Identify the domain of the function shown in the graph.

Leno4ka [110]

Domain is set of all x-values. You are supposed to focus on the x-axis instead.

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Answer

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3 years ago

Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)

jeyben [28]

Answer:

The vertex: $(\frac{3}{4},-\frac{41}{4} )$

The vertical intercept is: $y=-8$

The coordinates of the two intercepts of the parabola are $(\frac{3+\sqrt{41} }{4} , 0)$ and $(\frac{3-\sqrt{41} }{4} , 0)$

Step-by-step explanation:

To find the vertex of the parabola $4x^2-6x-8$ you need to:

1. Find the coefficients a, b, and c of the parabola equation

$a=4, b=-6, \:and \:c=-8$

2. You can apply this formula to find x-coordinate of the vertex

$x=-\frac{b}{2a}$ , so

$x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}$

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex ( $f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c$ )