Given : - Square ABCD with side 3. E and F as midpoints.
To find : - area of EBFD
Solution : - We have, area of square ABCD = 3 x 3 = 9 units.
Thus, (ar)EBFD = ar ABCD - ar DAE - arDCF
arDAE = 1/2 x base x height
=1/2 x 1.5 x 3 ( AE is 1/2 of AB = 1.5, DA is altitude)
= 2.25
arDFC = 1/2 x base x height
= 1/2 x 1.5 x 3 (FC is 1/2 of BC, DC is altitude)
= 2.25
Thus, (ar) EBFD = arABCD - arDAE - arDCF
= 9 - 2.25 - 2.25
= 4.5 units.
Thus, area of quad EBFD is 4.5 units.
8 is the answer if u do some equation gymnastics as i call them
Answer:
(7*100) can be written as 7*10^2
4 * / 100 i don’t know
if it was 4 * 100 then it’s 4*10^2
if it was divided then it’s 4*10^-2
8* 1/1000 = 8/1000 = 8*10^-3
add together to get 1.100008 * 10^3 (if it was 4*100)
or 7.00048 * 10^2 ( if it was 4/100)
4 500-60 = 4 440
4 440/38 = 116.8
At most they would be able to invite 116 people to the reception with their budget.
ANSWER
x= 46
EXPLANATION
To solve this problem you need to remember that a straight line is 180°. This figure is basically a straight line split in two, so 134°+x=180°. You can also subtract 134 from 180 to get 46.
