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storchak [24]
2 years ago
13

a newborn is treated for pulmonary valve stenosis; stretching of the valve opening is accomplished via a percutaneous balloon pu

lmonary valvuloplasty. what is the root operation?
Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
3 0

Answer:

dilation

Step-by-step explanation:

When the pulmonary valve does not work properly, it can interfere with blood flow from the heart to the lungs, as well as force the heart to work harder to carry the blood that is needed to the rest of the body. Some children have heart conditions present at the time of birth and may require repair or replacement of the pulmonary valve, this option has a lower risk of infection, preserves the strength and functioning of the valve, and eliminates the need to take medication.

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no clue try looking it up on here see what you find

Step-by-step explanation:

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According to Okun's law, if the unemployment rate goes from 7% to 4%, what will be the effect on the GDP?
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2 years ago
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12
Sergeu [11.5K]

Answer:

5 pints per hour.

Step-by-step explanation:

Morning:

Given:

Number of strawberries packed in every 4 minutes = 3

∴ Number of strawberries packed in every one minute = \frac{3}{4}

So, number of strawberries packed in every 60 minutes = \frac{3}{4}\times 60=45

1 hour = 60 minutes.

So, strawberries are packed at a rate of 45 pints per hour in the morning.

Afternoon:

Number of strawberries packed in every 3 minutes = 2

∴ Number of strawberries packed in every one minute = \frac{2}{3}

So, number of strawberries packed in every 60 minutes = \frac{2}{3}\times 60=40

1 hour = 60 minutes.

So, strawberries are packed at a rate of 40 pints per hour in the afternoon.

Difference between the packing rates is given as:

Morning rate - Afternoon rate = 45 - 40 = 5 pints per hour.

So, she packed 5 more pints in one hour in the morning than in the afternoon.

3 0
3 years ago
The number of column inches of classified advertisements appearing on Mondays in a certain daily newspaper is normally distribut
lana66690 [7]

Answer:

The probability there will be between 280 and 360 column inches of classified advertisement

P(280≤X≤360) = P(-2≤Z≤2) = 0.9544

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean  the population = 320

The standard deviation of the Population = 20

Let 'X' be the random variable in a normal distribution

Let 'X' = 280

Z = \frac{x-mean}{S.D} = \frac{280-320}{20} = -2

Let 'X' = 360

Z = \frac{x-mean}{S.D} = \frac{360-320}{20} = 2

<u><em>Step(iii):-</em></u>

The probability there will be between 280 and 360 column inches of classified advertisement

P(280≤X≤360) = P(-2≤Z≤2)

                        = P(z≤2) -P(z≤-2)

                       = P(z≤2)+P(z≤2)

                      = 2P(z≤2)

                     = 2×0.4772     ( from normal table)

                    = 0.9544

6 0
2 years ago
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