Is this relation a function?

kolbaska11 [484]

To find if a point is a solution to a system of equations, we need to plug in the x and y values of the point into each equation, and see if the equation is true.

Let's plug it into the first equation first:

-2(3) - 4(-2) might = 2
-6 + 8 = 2

The first equation is true.

Now, we need to check the second equation:

3(3) + 4(-2) might =8
9 - 8 does not = 8

Therefore, even if the point satisfies one equation, it does not satisfy the other. We can conclude that this is not a solution.

Hope this helps!

3 0

3 years ago

Ann started reading at 4:00 p.m. And finished at 4:20 p.m. Through what fraction of a circle did the minute hand turn?

Basile [38]

20/12???....................

8 0

3 years ago

Read 2 more answers

What is the height of a right triangle if its other two sides are 30 centimeters and 10 centimeters long?

Mila [183]

Answer:

Step-by-step explanation:

It depends on whether the 30 cm side is the hypotenuse, or one of the legs.

If the 30 cm side is the hypotenuse, then the third side is √(30^2-10^2) = √800 = 20√2 cm

If the 30 cm side is one of the legs, then the hypotenuse is √(30^2+10^2) = √1,000 = 10√10 cm

7 0

2 years ago

The lengths of three sides of a quadrilateral are shown below:

sasho [114]

Part A: To find the lengths of sides 1, 2, and 3, we need to add them together. We can do this by combining like terms (terms that have the same variables, or no variables).

(3y² + 2y − 6) + (3y − 7 + 4y²) + (−8 + 5y² + 4y)

We can now group them.

(3y² + 4y² + 5y²) + (2y + 3y + 4y) + (-6 - 7 - 8)

Now we simplify

12y² + 9y - 21

Part B: To find the length of the 4th side, we need to subtract the combined length of the 3 sides we know from the total length (perimeter).

(4y³ + 18y² + 16y − 26) - (12y² + 9y - 21)

Simplify, subtract like terms.

4y³ + (18y² - 12y²) + (16y - 9y) + (-26 + 21)

4y³ + 6y² + 7y - 5 is the length of the 4th side.

Part C (sorry for the bad explanation): A set of numbers is closed, or has closure, under a given operation if the result of the operation on any two numbers in the set is also in the set. For example, the set of real numbers is closed under addition, because adding any two real numbers results in another real number. Likewise, the real numbers are closed under subtraction, multiplication and division (by a nonzero real number), because performing these operations on two real numbers always yields another real number.

<em>Polynomials are closed under the same operations as integers. </em>

7 0

3 years ago

Para ir a visitar a los abuelos Paula y Mario se ponen de acuerdo en que Paula vaya cada 5 días y Mario cada 6 días. Si coincidi

photoshop1234 [79]

Answer:

a) January 24(24 de Enero)

b) Paula will have made 5 visits(Paula habrá hecho 5 visitas). Mario will have made 4 visits(Mario habrá hecho 4 visitas).

Step-by-step explanation:

When two events, A and B, happen every x and y days, respectively, they will happen on the same day in each lcm(x,y) days. lcm(x,y) is the lesser common multiple of x and y which is not 0.

In this question:

Paula each 5 days

Mario each 6 days

Multiples of 5: {0, 5, 10, 15, 20,25,30, ...}

Multiples of 6: {0, 6, 12, 18, 24, 30, ...}

a) ¿Cuándo volvieron a coincidir?

lcm(5,6) = 30

30 days from December 24, which is January 24(24 de Enero).

b) ¿Cuántas visitas habrá hecho cada uno?

Paula visits each 5 days.

30 is 6th non-zero multiple of 5. This means that on January 24 will be her 6th visit. So she will have made 5 visits.

30 is the 5th non-zero multiple of 6. This means that on January 24 will be her 5th visit. So he will have made 4 visits.

4 0

3 years ago