The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Answer:
c.
Step-by-step explanation:
Move the constant to the right side and the sign
0.5x=26-6
Calculate
0.5x=26-6=20 >>> 0.5x=20
divide both sides of by the equation 0.5
0.5x=20 >>> x=40
Answer:
Where are the graphs
Step-by-step explanation:
Answer:
using quaderatic expression solving problems of algebraic expressions.
Step-by-step explanation:
no1.
take the smallest side to be x
and the longest side to be x-1/3
then expand the expression equating to 30.
then solve for x value
Answer:
y = 2x - 200
Step-by-step explanation:
The function type that would model this relationship is linear because for each bracelet sold, the jazz band would increase their profit by $2. Since it has a consistent rate, it is linear. Using the slope-intercept formula of y = mx + b, where 'm' is the rate and 'b' is the initial value, you can use $2 for the rate or cost per bracelet and -$200 for the initial value or cost of supplies:
y = 2x - 200, where '2' is the cost per bracelet, 'x' the number of bracelets sold, '-200' is the cost for supplies and 'y' is the profit.
