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solniwko [45]
3 years ago
11

Imagine a machine that produces an output force that is five times larger

Computers and Technology
1 answer:
gladu [14]3 years ago
7 0

Answer:

M.A =  \frac{output}{input}  \\ let \: input \: force \: be \: x \\ hence \: output \: force \:  = 5x \\ M.A =  \frac{5x}{x}  \\  = 5

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4 years ago
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Write a program that asks the user to input an integer named numDoubles. Create a dynamic array that can store numDoubles double
Hitman42 [59]

Answer:

Answered in C++

#include <iostream>

using namespace std;

int main() {

   int size;

   cout<<"Length of array: ";

   cin >> size;

   double *numDoubles = new double[size];

   double sum =0;

   cout<<"Array Elements: ";

   for(int i=0;i<size;i++){

       cin>>numDoubles[i];

       sum += numDoubles[i];

   }

   delete [] numDoubles;

   cout<<"Average: "<<sum/size;

   return 0;  

}

Explanation:

This line declares the size (or length) of the array

<em>    int size; </em>

This line prompts the user for the array length

<em>    cout<<"Length of array: "; </em>

This gets the input from the user

<em>    cin >> size; </em>

This dynamically declares the array as of double datatype

<em>    double *numDoubles = new double[size]; </em>

This declares and initializes sum to 0

<em>    double sum =0; </em>

This prompts the user for elements of the array

<em>    cout<<"Array Elements: "; </em>

The following iteration gets input from the user and also calculates the sum of the array elements

<em>    for(int i=0;i<size;i++){ </em>

<em>        cin>>numDoubles[i]; </em>

<em>        sum += numDoubles[i]; </em>

<em>    } </em>

This deletes the array

<em>    delete [] myarray; </em>

This calculates and prints the average of the array

<em>    cout<<"Average: "<<sum/size; </em>

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3 years ago
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Answer:

im not sure

Explanation: is their supposed to be a picture or something?

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________ is the information about a file.
GalinKa [24]
Properties is the information about the file
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3 years ago
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