We have the <span> Trigonometric Identities : </span>secx = 1/cosx; (sinx)^2 + (cosx)^2 = 1;
Then, 1 / (1-secx) = 1 / ( 1 - 1/cosx) = 1 / [(cosx - 1)/cosx] = cosx /
(cosx - 1 ) ;
Similar, 1 / (1+secx) = cosx / (1 + cosx) ;
cosx / (cosx - 1) + cosx / (1 + cosx) = [cosx(1 + cosx) + cosx (cosx - 1)] / [ (cosx - 1)(cox + 1)] =[cosx( 1 + cosx + cosx - 1 )] / [ (cosx - 1)(cox + 1)] = 2(cosx)^2 / [(cosx)^2 - (sinx)^2] = <span> 2(cosx)^2 / (-1) = - 2(cosx)^2;
</span>
Answer:
B
Step-by-step explanation:
i gottt youu
Answer: The common difference is 8
Step-by-step explanation:
First Use the formula for the second to generate the first two numbers.
= 2^3n-2
Put in 1 for the first term and you will get 2 and the second term is 16 and to get from 2 to 16 you will multiply by 8.
The easy way is just to divide by 3
15% /3 = 5%
Since you have divided the % by 3 you can divide the 375 by 3
375 / 3 = 125
Answer 125
Let smaller no be x and bigger be y
- x+y=39--(1)
- 3x=y+81
- y=3x-81
- y=3(x-27)--(2)
Put it in eq(1)
- x+3(x-27)=39
- x+3x-81=39
- 4x=81+39
- 4x=120
- x=30
Now
The numbers are 9 and 30
