All categories

3 years ago

SOMEONE PLS HELP ME WITH ASAP

Mathematics

2 answers:

Levart [38]3 years ago

7 0

Answer:

area of trapezium in terms of x=1/2*x(x+3+x+1)

Step-by-step explanation:

ollegr [7]3 years ago

6 0

Answer:

(x^2 + 2x) cm^2

Step-by-step explanation:

Area of trapezium = 1/2 (a+b)h

= 1/2 [(x+3)+(x+1)] (x)

=1/2 (2x+4)(x)

= 1/2 (2x^2 + 4x)

= x^2 + 2x

You might be interested in

What does a cop never forget to say

Kruka [31]

Probably they never forget to give the Miranda warning.

8 0

2 years ago

A study concludes that 15 percent of all college students attend a gym class. Which of the following statements is true? 15 perc

yanalaym [24]

I think it is 15 percent is a statistic.
I am not 100% sure if it is right or not but I hope it helps!

4 0

3 years ago

Read 2 more answers

Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

2 years ago

Read 2 more answers

What is the probability of flipping 4 coins and having exactly three of them land on tails?

Elodia [21]

3/4 coins are heads:
THHH
HTHH
HHTH
HHHT

4 chances

2 options of heads/tails with 4 coins

2*2*2*2= 16

4/16 :)

4 0

3 years ago

HOW do you find the value of TAN 88 degrees 22' 45'' and COT 36 degrees???

storchak [24]

Part 1
We want to find the tan of 88 degrees, 22' 45''.

88° 22' 45''
= 88 + 22/60 + 45/3600 degrees
= 88.3792°

From the calculator, obtain
tan(88.3792°) = 35.3409

Answer: 35.3409

Part 2
We want to find cot(36°).

By definition, cot(x) = 1/tan(x).
From the calculator, obtain
tan(36°) = 0.7265
Therefore
cot(36°) = 1/0.7265 = 1.3764

Answer: 1.3764

3 0

3 years ago