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spin [16.1K]
3 years ago
5

the longest side of a right-angled triangle is 13 cm. if the perimeter of the triangle is 30 cm, find the shortest side

Mathematics
1 answer:
sasho [114]3 years ago
7 0

Answer:

The shortest side = 5

Step-by-step explanation:

Call one  side = a

The middle side = b

the hypotenuse = c

a^2 + b^2 = c^2

a^2 + b^2 = 13^2

a^2 + b^2 = 169

a + b + c = 30

a + b + 13 = 30

a + b = 17

b = 17 - a

a^2 + b^2 = 169

a^2 + (17 -  a)^2 = 169

a^2 + (289 - 34a + a^2) = 169

a^2 + a^2 - 34a + 289 = 169           Subtract 169 from both sides

2a^2 - 34a + 289 - 169 = 0

2a^2 - 34a + 120 = 0                      Divide by 2

a^2 - 17a + 60 = 0

This quadratic is easily factored. You need two numbers that add to - 17 and multiply to 60

(a - 5) * (a - 12) = 0    Both give you positive answers. You only want the shortest side

a - 5 = 0

a = 5                                              Is 5 the shortest side?

a - 12 = 0

a = 12                                           Yes 5 is the shortest side.

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kobusy [5.1K]

Answer:

x = - 2

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Step-by-step explanation:

The best way to do this is to put - 3x in for y in the second equation.

4x - 2(-3x) = - 20        Watch the signs. You have 2 minus signs.

4x - - 6x = -20            Change - - 6x to 6x

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x = -20/10

x = - 2

============================

Find y

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Answer:

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Step-by-step explanation:

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