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garri49 [273]
2 years ago
5

A grocer has 2 kinds of tea, one that sells for $8.00 per pound and the other that sells for $6.00 per pound. How many pounds of

each kind must he use to make 50 pounds of tea that will sell for $7.40 per pound?
Answer in _____ pounds of $8.00 tea and _____ pounds of $6.00 tea
ASAP-WILL MARK BRANLIEST!
Mathematics
2 answers:
Brilliant_brown [7]2 years ago
3 0

Answer:

35 pounds of $8.00 tea and 15 pounds of $6.00 tea

Step-by-step explanation:

Let x represent the pounds of tea of the $8 kind. 8x would represent the total cost of that type of tea. We can also say 50 - x is the pounds of tea of the $6 kind, so 6(50 - x) is the total cost of that type of tea. 50 * 7.4 represents the total cost of all the tea, and the expression 8x + 6(50 -x) would also represent the same thing. We can write this as an equation,

8x + 6(50 -x) = 50 * 7.4

simplify,

8x + 300 - 6x = 370

2x + 300 = 370

and solve.

2x = 70

x = 35

This means there is 35 pounds of the $8 kind.

We can subtract that from 50 to find,

50 - 35 = 15,

15 pounds is the amount of the $6 kind.

dsp732 years ago
3 0

Answer:

amount of $8 tea = 35 lb

amount of $6 tea = 15 lb

Step-by-step explanation:

Let x = amount of $8 tea

Then 50 - x =  amount of $6 tea

Total cost of $8 tea is = 8x

Total cost of $6 tea = 6(50 - x)

Total cost of $7.40 tea = 7.4(50)

Total cost of $8 tea + Total cost of $6 tea = Total cost of $7.40 tea

8x + 6(50 - x) = 7.4(50)

8x + 300 - 6x = 370

2x = 70

x = 35

50 - x = 15

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