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Andrew [12]
2 years ago
10

El navegador= blank de web

Spanish
2 answers:
storchak [24]2 years ago
6 0
I don't understand the question
marin [14]2 years ago
3 0
El navegador = el explorador de web
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Que apartados constituyen una sección​
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Explanation:

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Simplify x^3-125/2x-10
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We \ first, \ simplify \  \frac{125}{2} \\ \\   \left[\begin{array}{ccc}((x^3)-( \frac{125}{2}*x))-10 \end{array}\right] \\ \\ \boxed{\boxed{x^3= \frac{x^3}{1} = \frac{x^3*2}{2} }} \\ \\ \\ \boxed{ \frac{x^3*2-(125x)}{2} = \frac{2x^3-125x}{2} } \\ \\ \\ \frac{(2^3-125x}{2} -10 \\ \\  pulling \ out \ like \ factors : \\ \\  2x^3 - 125x  =   x * (2x^2 - 125) \\ \\ Factoring: \  2x^2 - 125

<span>Here's how!</span>

Proof :  \ (A+B) * (A-B) =\\&#10;         A2 - AB + BA - B2 =\\&#10;         A2 - AB + AB - B2 = \\&#10;         A2 - B2\\

<span>Therefore</span> . . . 

\boxed{ \frac{x*(2x^2-125)-(10*2)}{2} = \frac{2x^3-125x-20}{2} }

<span>The factors would then be the following:</span>

→ ( Leading \  Coefficient :  1,2)
→ (Trailing Constant) :  1 ,2 ,4 ,5 ,10 ,20

By then, understanding on how we have got in our terms, such as the like terms, and also how we have understanded the coefficient's, we would then have our answer clear below.

\leadsto \ Your \ answer: \boxed{\bf{ \frac{2x^3-125x-20}{2} }} <span>✔</span>
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A would be the correct answer
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