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zmey [24]
3 years ago
15

Tony sold t-shirts and hats at the festival. He made a $4 profit for each t-shirt he sold. He also made a profit of $34 from sel

ling hats. If he made a total profit of $106, how many t-shirts did he sell?
Mathematics
2 answers:
nataly862011 [7]3 years ago
8 0
18 t shirts

106 - 34 = 72
72 / 4 = 18
Nataly_w [17]3 years ago
5 0

Answer:

18 T-shirts

Step-by-step explanation:

$4×18= $72 $72+$34=$106

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Plz help real quick
Maru [420]

Answer:

what are I am help you are not explaining so explain me

8 0
2 years ago
Suppose the ages of multiple birth mothers (4 or more births) are normally distributed with a mean age of 35.5 years and a stand
Ann [662]

Answer:

40.65% of these mothers are between the ages of 32 to 40

23.27% of these mothers are less than 30 years old

37.07% of these mothers are more than 38 years old

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 35.5, \sigma = 7.5

What percent of these mothers are between the ages of 32 to 40?

This is the pvalue of Z when X = 40 subtracted by the pvalue of Z when X = 32.

X = 40

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 35.5}{7.5}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 32

Z = \frac{X - \mu}{\sigma}

Z = \frac{32 - 35.5}{7.5}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192

0.7257 - 0.3192 = 0.4065

40.65% of these mothers are between the ages of 32 to 40

What percent of these mothers are less than 30 years old?

This is the pvalue of Z when X = 30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 35.5}{7.5}

Z = -0.73

Z = -0.73 has a pvalue of 0.2327

23.27% of these mothers are less than 30 years old

What percent of these mothers are more than 38 years old?

This is 1 subtracted by the pvalue of Z when X = 38.

Z = \frac{X - \mu}{\sigma}

Z = \frac{38 - 35.5}{7.5}

Z = 0.33

Z = 0.33 has a pvalue of 0.6293

1 - 0.6293 = 0.3707

37.07% of these mothers are more than 38 years old

5 0
3 years ago
The population of Bridgetown triples every decade. If the population
Afina-wow [57]
Between 2000 and 2030 three decades will have gone by, which means the population will triple three times.

2000-25,000 \\ 2010-25,000*3=75,000 \\ 2020-75,000*3=225,000 \\ 2030-225,000*3=675,000

Therefore, the population of Bridgetown will be 675,000 people in 2030.
4 0
3 years ago
Yuri purchased 8 trees to have planted at his house. The store charged a delivery fee of $5 per tree.
cestrela7 [59]

Answer:

$16.

Step-by-step explanation:

Let t represent the cost of each tree.

We have been given that Yuri purchased 8 trees to have planted at his house. So the cost of 8 trees will be 8t.

We are also told that the store charged a delivery fee of $5 per tree. So the delivery charges of 8 trees will be 8\times \$5=\$40

The total cost of purchasing 8 trees will be 8t+40.  

Since the total cost of the trees including the delivery was $168, so we can get an equation as:

8t+40=168

8t+40-40=168-40

8t=128

Upon dividing both sides of our given equation by 8, we will get:

\frac{8t}{8}=\frac{128}{8}  

t=16  

Therefore, the cost of each tree is $16.

5 0
3 years ago
Mike is renting a boat. The rental fee is $25 for each hour. He rented a boat for 3 hours. Which is the dependent variable in th
egoroff_w [7]
225  i think not sure 
7 0
3 years ago
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