Answer:
Between minus one and zero
Step-by-step explanation:
The answer is between minus one amd zero
Answer:
A altura máxima é 5
Step-by-step explanation:
Matematicamente, a altura máxima pode ser obtida
A altura máxima é simplesmente o vértice da parábola
Começamos diferenciando a função Isso será -8x
Agora, defina -8x como 0
Isso significa que x = 0
Agora, substitua x = 0 de volta na equação temos
f (0) = -4 (0) ^ 2 + 5
f (0) = 5
A altura máxima é 5
Rewrite the given y – 8 = 1/2(x – 4), replacing "y" with "f(x)."
Then f(x) – 8 = 1/2(x – 4)
Multiply all 3 terms by 2 to eliminate the fraction (1/2):
2f(x) = 16 + x - 4
Combine like terms: 2f(x) = x + 12
x + 12
Divide both sides by 2: f(x) = -----------
2
Note that this is equivalent to f(x) = (1/2)x + 6. Important: Use parentheses as indicated.
Answer:
0.289792.
Step-by-step explanation:
If we define a month with one or more accident as "success"; and
A month with no accident as "failure" .
- P(one or more accidents will occur during any given month)=0.60.
- P(no accident will occur during any given month)=1-0.60=0.40
We want to calculate the probability that there will be at least four months in which no accidents occur before the fourth month in which at least one accident occurs.
in this case, let k=number of failures before the fourth success
Therefore, 
k follows a negative binomial distribution.
Therefore, the probability is:
![P(k\geq 4)=1-P(k\leq 3)\\=1-\sum_{k=0}^{3}\left(\begin{array}{ccc}3+k\\k\end{array}\right)(0.60)^4(0.40)^k\\=1-(0.60)^4 \left[\left(\begin{array}{ccc}3\\0\end{array}\right)(0.40)^0+\left(\begin{array}{ccc}4\\1\end{array}\right)(0.40)^1+\left(\begin{array}{ccc}5\\2\end{array}\right)(0.40)^2+\left(\begin{array}{ccc}6\\3\end{array}\right)(0.40)^3\right]\\=1-(0.60)^4 \left[ 1+1.6+1.6+1.28\right]\\=1-(0.60)^4[5.48]\\=0.289792](https://tex.z-dn.net/?f=P%28k%5Cgeq%204%29%3D1-P%28k%5Cleq%203%29%5C%5C%3D1-%5Csum_%7Bk%3D0%7D%5E%7B3%7D%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D3%2Bk%5C%5Ck%5Cend%7Barray%7D%5Cright%29%280.60%29%5E4%280.40%29%5Ek%5C%5C%3D1-%280.60%29%5E4%20%5Cleft%5B%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C0%5Cend%7Barray%7D%5Cright%29%280.40%29%5E0%2B%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C1%5Cend%7Barray%7D%5Cright%29%280.40%29%5E1%2B%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C2%5Cend%7Barray%7D%5Cright%29%280.40%29%5E2%2B%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D6%5C%5C3%5Cend%7Barray%7D%5Cright%29%280.40%29%5E3%5Cright%5D%5C%5C%3D1-%280.60%29%5E4%20%5Cleft%5B%201%2B1.6%2B1.6%2B1.28%5Cright%5D%5C%5C%3D1-%280.60%29%5E4%5B5.48%5D%5C%5C%3D0.289792)
The required probability is 0.289792.
Answer:
Your answer is
That man buy 2 shirts in Rs 410.25.
He sold 1st shirt at Rs 451.275 where he profited 10%.
He sold 2nd shirt at Rs 348.7 where he lost 10%.
Total sold = 2 shirts = (451.275+348.7)= 800(About)
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