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Alexandra [31]
3 years ago
13

What are the first 3 multiples of 13

Mathematics
2 answers:
Lorico [155]3 years ago
7 0
Multiples: 13,26,39,52,65
Reptile [31]3 years ago
3 0
13 x 1 = 13
13 x 2 = 26
13 x 3 = 39
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PLS HELP ASAP!!!!<br> Determine whether each relation is a function. Explain your reasoning.
V125BC [204]
Each domain needs to have one range every x can only have 1 y they can be the same y value so...

Yes it is a function
6 0
3 years ago
Twelve decreased by twice a number is -34
Irina18 [472]
Hey there!

12 decreased by twice a number is -34.

Decreased= -

Twice=2

Number=n

2n-12= -34

I hope this helps!
~Kaikers
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3 years ago
The time a randomly selected individual waits for an elevator in an office building has a uniform distribution with a mean of 0.
Amiraneli [1.4K]

Answer:

The mean of the sampling distribution of means for SRS of size 50 is \mu = 0.5 and the standard deviation is s = 0.0409

By the Central Limit Theorem, since we have of sample of 50, which is larger than 30, it does not matter that the underlying population distribution is not normal.

0% probability a sample of 50 people will wait longer than 45 seconds for an elevator.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size, of at least 30, can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.5, \sigma = 0.289

What are the mean and standard deviation of the sampling distribution of means for SRS of size 50?

By the Central Limit Theorem

\mu = 0.5, s = \frac{0.289}{\sqrt{50}} = 0.0409

The mean of the sampling distribution of means for SRS of size 50 is \mu = 0.5 and the standard deviation is s = 0.0409

Does it matter that the underlying population distribution is not normal?

By the Central Limit Theorem, since we have of sample of 50, which is larger than 30, it does not matter that the underlying population distribution is not normal.

What is the probability a sample of 50 people will wait longer than 45 seconds for an elevator?

We have to use 45 seconds as minutes, since the mean and the standard deviation are in minutes.

Each minute has 60 seconds.

So 45 seconds is 45/60 = 0.75 min.

This probability is 1 subtracted by the pvalue of Z when X = 0.75. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.75 - 0.5}{0.0409}

Z = 6.11

Z = 6.11 has a pvalue of 1

1-1 = 0

0% probability a sample of 50 people will wait longer than 45 seconds for an elevator.

8 0
3 years ago
State the degree and leading coefficient of each polynomial in one variable. If it is not a polynomial in one variable, explain
musickatia [10]
1.\\-6x^6-4x^5+13xy\\degree:6\\it's\ not\ a\ polynominal\ in\ one\ variable\ (13x\boxed{y})\\\\2.\\8x^5-12x^6+14x^4-9\\degree:5\\leading\ coefficient:8\\\\3.\\15x+4x^3+3x^3-5x^4\\degree:4\\leading\ coefficient:-5

4.\\(d+5)(3d-4)=3d^2-4d+15d-20\\degree:2\\leading\ coefficient:3\\\\5.\\6x^5-5x^4+2x^9-3x^2\\degree:9\\leading\ coefficient:2

3 0
3 years ago
The length of a rectangle is 9 centimeters more than half
Sedaia [141]

Answer:

l = 16 cm

Step-by-step explanation:

Let's set the width of the rectangle as "w" and the length of the rectangle as "w/2 + 9".

The perimeter of a rectangle is calculated by adding up the value of all of its side lengths. Therefore, we can find the perimeter using 2l + 2w = P.

We can substitute 60 for P and w/2 + 9 for l.

  • 2(w/2 + 9) + 2w = 60
  • 2w/2 + 18 + 2w = 60
  • w + 18 + 2w = 60
  • 3w + 18 = 60
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  • w = 14

Substitute w = 14 into the equation for length l.

  • l = w/2 + 9
  • l = 14/2 + 9
  • l = 16

The length of the rectangle is 16 cm.

4 0
3 years ago
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