Question

1. Four cards are drawn at random without replacement from a standard deck of 52 cards. Compute the probability that all are of different suits. 2. An urn contains 5 green, 6 blue, and 4 red balls. You take 3 balls out of the urn, one after the other, without replacement. Compute the probability that the third ball is red given that the first two balls are green. 3*. (Bayes Formula

Answer 1

Answer:

1) 10.55%

2) 30.77%

Step-by-step explanation:

52/52•39/51•26/50•13/49 = 0.105498... ≈ 10.55%

100% chance you draw a unique card on the first draw

51 cards left of which 13(3) = 39 are unique suit for your second draw

50 cards left of which 13(2) = 26 are unique suit for your third draw

49 cards left of which 13(1) = 13 are unique suit for your forth draw.

Two balls are already green

Leaves 4 red balls in a field of 13 balls

4/13 = 0.307692... ≈ 30.77%