Question

Write a C++ Program that contains one user defined function cal_grades().  In main() function: o Prompt user to enter obtained(0 - 100) marks for one subject. o Call cal_grades(marks_subject). o Print the corresponding Grade with respect to Marks.  In user defined function: o Perform conditioning with else if statement return char value. o Function must return value.

Answer 1

Answer:

# include <iostream>

#include<conio.h>

using namespace std;

char grade(int marks);

main()

{

int subject 1, subject 2, subject 3, subject 4, subject 5, sum, percentage;

char G;

cout<<"enter marks of subject 1";

cin>>subject 1;

cout<<"enter marks of subject 2";

cin>>subject 2;

cout<<"enter marks of subject 3";

cin>>subject 3;

cout<<"enter marks of subject 4";

cin>>subject 4;

cout<<"enter marks of subject 5";

cin>>subject 5;

G = grade (subject 1);

cout<<"Grade of Subject 1"<< G;

G = grade (subject 2);

cout<<"Grade of Subject 2"<< G;

G = grade (subject 3);

cout<<"Grade of Subject 3"<< G;

G = grade (subject 4);

cout<<"Grade of Subject 4"<< G;

G = grade (subject 5);

cout<<"Grade of Subject 5"<< G;

sum = Subject 1 +Subject 2 +Subject 3 +Subject 4 + Subject 5;

Percentage =  sum/500*100;

G = grade (percentage);

cout<<"Overall Grade"<< G;

getch();

}

char grade(int marks)

{

int marks;

char 'A', 'B' , 'C' , 'D' , 'F';

if (marks >80)

{

return 'A';

}

else

if (marks >70 && marks< 80 )

{

return 'B';

}

else

if (marks >60 && marks< 70 )

{

return 'C';

}

else

if (marks >50 && marks< 60 )

{

return 'D';

}

else

return 'F';

}

The program will compute the percentage of the marks obtained, then with the help of this percentage score the output will be determined by function named as Grade.