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goldenfox [79]
2 years ago
8

Plz help me with this

Mathematics
2 answers:
gladu [14]2 years ago
6 0

Answer:

2nd one

Step-by-step explanation:

(x*x*x*x*x*x*x*x*x)

or x^9

victus00 [196]2 years ago
6 0

It’s x^9... the (x^3)^4 is the same thing as x^3•x^3•x^3•x^3=x^12 (you add the exponents when the equation is spread out...so 3+3+3+3=12~that’s how I got the ^12 part)

Now u have x^12•x^-3. And before I added the exponents, so imma do it again. 12-3=9 so the answer is x^9

If this was too confusing just give the variable a number (like 4) and see if 4^12•4^-3 has the same solution as 4^9

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Using Heron's Formula, find the Area.<br> Sides are 7 13 8
Amanda [17]

Answer:

10.3

Step-by-step explanation:

hope this helps, if any genius answers as well, give brainliest to them

5 0
2 years ago
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15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find<br>dy/dx at =22/7*4<br>​
Sav [38]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}

It looks like we're given

\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}

where <em>a</em> and <em>b</em> are presumably constant.

Recall that

\cos^2t=\dfrac{1+\cos(2t)}2

\sin^2t=\dfrac{1-\cos(2t)}2

so that

\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}

Then we have

\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t

\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}

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where the last reduction follows from dividing through everything by \cos(2t)\cos^2t and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0
3 years ago
Sean is helping his dad build a tiled walkway in their backyard. The walkway will be 60 feet long and 2 feet wide. The local har
Natalija [7]
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Width of the walkway that needs to be tiled = 2 feet.
Then
Area of the walkway that needs to be tiled = Length * Breadth
                                                                    = 60 * 2 square feet
                                                                    = 120 square feet
Now
Length of the tiles sold by the local store = 2 feet
Width of the tiles sold by the local store = 2 feet
Area covered by the tiles sold by the local store = 2 * 2 feet
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Number of tiles in a box = 6
Then
Total area covered by a box of tile = (6 * 2) square feet
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The number of boxes required by Sean = (120/12)
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So 10 boxes of tiles are needed by Sean and his father.
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netineya [11]
Now, check the picture below

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