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2 years ago

Giving brainliest! Please show the working out

Mathematics

1 answer:

tiny-mole [99]2 years ago

7 0

Answer:

see explanation

Step-by-step explanation:

(a)

OC = OB ( both radii of the circle )

Thus Δ BOC is isosceles with congruent base angles.

∠ BOC = ∠ BCO = 50°

(b)

∠ ACB = 90° ( angle in a semicircle ), then

∠ ACO = 90° - 50° = 40°

OA = OC ( both radii of the circle )

Thus Δ ACO is isosceles with congruent base angles.

∠ BAC = ∠ ACO = 40°

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I need help with twelve plz

EleoNora [17]

12)
9/10 / 3/4
= 9/10 * 4/3
= 12/10
= 6/5

5 0

2 years ago

Timed quiz help please! 2 2/5 kilometers in 3 3/4 minuets.

shepuryov [24]

Answer: 16/25 (sorry I'm not really sure bc I'm just a middle schooler)

Step-by-Step explanation:

2 2/5 km=2.4 kilometers

3 3/4 minutes=3.75 minutes

2.4/3.75=240/375

240/375=48/75=16/25=64/100=0.64

0.64 km/minute (0.64 km per minute)

you can solve the problem using the fractions...

2 2/5=12/5

3 3/4=15/4

(12/5)/(15/4)=(12/5)*(4/15)=48/75=16/25=0.64 again, or you can simplify before multiplying...

(12/5)/(15/4)=(12/5)*(4/15)=(4/5)*(4/5)=16/25...

4 0

2 years ago

Apply the order of operations to simplify each expression.

Nuetrik [128]

Answer:

your right it is 12 great job!

Step-by-step explanation:

7 0

1 year ago

Read 2 more answers

Kala takes classes at both Westside Community College and Pinewood Community College. At Westside, class fees are $98 per credit

masya89 [10]

Answer:

T=98W-115W+1840

Step-by-step explanation:

$98 per credit at Westside (W)

$115 per credit at Pinewood (P)

Expression 1 : 98W+115P=T

Expression 2 : W+P=16

Combined: if W=16-P

Total=98W+115(16-W)

T=98W-115W+1840

3 0

1 year ago

1. If x=3-√3, prove that x² +36 x² = x²

valentina_108 [34]

Answer:

we get $x^2=12-6\sqrt{3}$

Step-by-step explanation:

We are given: $x=3-\sqrt{3}$

We need to find $x^2$

Note: Since question is not clear, I am assuming that we need to find $x^2$

Solving:

$x=3-\sqrt{3} \\Taking \ square \ on \ both \ sides\\x^2=(3-\sqrt{3})^2\\$

We know that $(a-b)^2= a^2-2ab+b^2$

Using formula and simplifying

$x^2=(3)^2-2(3)(\sqrt{3})+(\sqrt{3})^2\\x^2=9-6\sqrt{3} +3\\x^2=12-6\sqrt{3} \\$

So, we get $x^2=12-6\sqrt{3}$

3 0

2 years ago