Answer:
85%?
Step-by-step explanation:
going between so im guessing.
The missing digits is highlighted in bold form
A study done by researchers at a university concluded that 70% of all student-athletes in this country have been subjected to some form of hazing. The study is based on responses from 1800 athletes. What are the margin of error and 95% confidence interval for the study?
Answer:
Step-by-step explanation:
Given that:
The sample proportion 
The sample size n = 1800
At 95% confidence interval level:
The level of significance = 1 - 0.95 = 0.05
Critical value: 
Thus, the Margin of Error E = 




the Margin of Error E = 0.021
At 95% C.I for the population proportion will be:

= 0.70 ± 0.021
= (0.70 - 0.021, 0.70 + 0.021)
= 0.679, 0.721)
Answer:
<u>3.63 years</u>
Step-by-step explanation:
The formula would be of compound growth, which is:

Where
F is future amount (with interest)
P is initial deposit
r is rate of interest in a year
n is number of compounding in 1 year
t is the time in years
Given in this problem:
To accumulate 2000 interest means the future amount will be:
10000+2000 = 12,000
Present amount is 10,000
r is the annual interest, which is 5% or 0.05
compounded monthly means, 12 times a year, so n = 12
t is time in years, which we need to find
Substituting, we have:

The time it will take is around <u>3.63 years</u>
75% in fraction is 3/4 and the decimal is 0.75
MxM=M^2 (m squared)
Highest variable comes first, so it'd be m^2+5m+6
(m+2)(m+3) is your answer. That is it factored. If that equation equals 0, then m=-2 or -3