Answer:
3 hours and 15 min is how long he practiced
Answer: 32 2/19°F
Step-by-step explanation:
Since the temperature was 52° and dropped to 38°, the difference will be:
= 52° - 38°
= 14°
Therefore, 14° was dropped in 4¾ hours. Therefore, the temperature dropped pee hour will be:
= 14/4¾
= 14 / 19/4
= 14 × 4/19
= 56/19
= 2 18/19° per hour.
In 2 hours, the temperature dropped will be:
= 2 18/19° × 2
= 5 17/19°
With the above explanation, the temperature after 2 hours will then be:
= 38° - 5 17/19°
= 32 2/19°F
The temperature will be 32 2/19°F.
price of 3Step-by-step explanation:
Answer:
f
(
x
)
=
5
x
2
−
2
x
+
3
g
(
x
)
=
4
x
2
+
7
x
−
5
f
(
g
(
x
)
)
=
5
(
4
x
2
+
7
x
−
5
)
2
−
2
(
4
x
2
+
7
x
−
5
)
+
3
=
80
x
4
+
280
x
3
+
45
x
2
−
350
x
+
125
−
8
x
2
−
14
x
+
10
+
3
=
80
x
4
+
280
x
3
+
45
x
2
−
8
x
2
−
350
x
−
14
x
+
125
+
10
+
3
f
(
g
(
x
)
)
=
80
x
4
+
280
x
3
+
37
x
2
−
364
x
+
138
The answer is
f
(
g
(
x
)
)
=
80
x
4
+
280
x
3
+
37
x
2
−
364
x
+
138
.
Step-by-step explanation:
Answer:
<em>t = 65 - 4d</em>
Step-by-step explanation:
<u>Linear Modeling</u>
The temperature in St. Louis dropped by 4 degrees every day in one week.
When d days have passed, the temperature will have dropped by 4d degrees.
We know the temperature t at the beginning of the week was 65 degrees.
Thus, when d days pass, the linear model for the temperature t is:
t = 65 - 4d
