Answer:
B and C
(I'm not sure if b and e are supposed to be the same though) if they are then, b, c, and e
Answer:
![x+2y=-11](https://tex.z-dn.net/?f=x%2B2y%3D-11)
Step-by-step explanation:
Slope intercept form of a line is given by:
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
Where
m is the slope and b is the y-intercept
Given slope is ![-\frac{1}{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D)
We can write:
![y=-\frac{1}{2}x+b](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B2%7Dx%2Bb)
Now to find b, we replace x with -3 and y with -4, given, so we have:
![y=-\frac{1}{2}x+b\\-4=-\frac{1}{2}(-3)+b\\-4=\frac{3}{2}+b\\b=-5.5](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B2%7Dx%2Bb%5C%5C-4%3D-%5Cfrac%7B1%7D%7B2%7D%28-3%29%2Bb%5C%5C-4%3D%5Cfrac%7B3%7D%7B2%7D%2Bb%5C%5Cb%3D-5.5)
So, the equation is:
![y=-\frac{1}{2}x-\frac{11}{2}](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B2%7Dx-%5Cfrac%7B11%7D%7B2%7D)
Now,
The standard form is given by:
![Ax+By=C](https://tex.z-dn.net/?f=Ax%2BBy%3DC)
So, we take x and y to left side and the constant to right side. Rearranging, we get:
![y=-\frac{1}{2}x-\frac{11}{2}\\2y=-x-11\\x+2y=-11](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B2%7Dx-%5Cfrac%7B11%7D%7B2%7D%5C%5C2y%3D-x-11%5C%5Cx%2B2y%3D-11)
The first answer choice is right.
Answer:
(mxt) miles
Step-by-step explanation:
![speed = m \: miles \: per \:minute \\ time \: = t \: minutes \\ speed = \frac{distance}{time} \\ m = \frac{d}{t} \\ m \times t \: = d \\ d = (m \times t)miles](https://tex.z-dn.net/?f=speed%20%3D%20m%20%5C%3A%20miles%20%5C%3A%20per%20%5C%3Aminute%20%5C%5C%20time%20%5C%3A%20%20%3D%20t%20%5C%3A%20minutes%20%5C%5C%20speed%20%3D%20%20%5Cfrac%7Bdistance%7D%7Btime%7D%20%20%5C%5C%20m%20%3D%20%20%5Cfrac%7Bd%7D%7Bt%7D%20%20%5C%5C%20m%20%5Ctimes%20t%20%5C%3A%20%20%3D%20d%20%5C%5C%20d%20%3D%20%28m%20%5Ctimes%20t%29miles)
hope that this is helpful.
The answer to the question
Answer:
Option 2: ![\sin(30)=\frac{1}{2}](https://tex.z-dn.net/?f=%5Csin%2830%29%3D%5Cfrac%7B1%7D%7B2%7D)
Step-by-step explanation:
Given:
From the triangle shown below;
A triangle QRS with angle QRS = 90°, ∠QSR = 30°.
Side QR = 5, SQ = 10 and RS = 5√3
Now, we know from trigonometric ratio that,
![\sin (A) = \frac{Opposite\ side}{Hypotenuse}](https://tex.z-dn.net/?f=%5Csin%20%28A%29%20%3D%20%5Cfrac%7BOpposite%5C%20side%7D%7BHypotenuse%7D)
Here, opposite side of angle QSR is QR and Hypotenuse is the side opposite angle QRS which is SQ. Therefore,
![\sin(\angle QSR)=\dfrac{QR}{SQ}\\\\\\\sin(30)=\dfrac{5}{10}\\\\\\\sin(30)=\dfrac{5}{2\times 5}=\dfrac{1}{2}](https://tex.z-dn.net/?f=%5Csin%28%5Cangle%20QSR%29%3D%5Cdfrac%7BQR%7D%7BSQ%7D%5C%5C%5C%5C%5C%5C%5Csin%2830%29%3D%5Cdfrac%7B5%7D%7B10%7D%5C%5C%5C%5C%5C%5C%5Csin%2830%29%3D%5Cdfrac%7B5%7D%7B2%5Ctimes%205%7D%3D%5Cdfrac%7B1%7D%7B2%7D)
Therefore, the value of sine of 30° is one-half. So, second option is correct.