Answer:
1000 mM
Explanation:
Using V = -60 mV㏒₁₀[K/K'] where V = membrane potential = -60 mV, K = intracellular concentration = unknown and K' = extracellular concentration = 100 mM
So, V = -60 mV㏒₁₀[K/K']
-60 mV = -60 mV㏒₁₀[K/K']
dividing both sides by -60mV, we have
-60 mV/-60 mV = ㏒₁₀[K/K']
㏒₁₀[K/K'] = 1
taking antilogarithm of both sides, we have
[K/K'] = 10¹
multiplying both sides by K', we have
K = 10K'
K = 10 × 100 mM
K = 1000 mM
So, the intracellular Cl- concentration is 1000 mM
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Answer:
What stages of aerobic respiration needs oxygen to happen?
The Krebs cycle and the electron transport system