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aev [14]
3 years ago
8

Does this shape have 4 Right Angles​

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
6 0
No a rhombus can not have 4 right angles
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What’s the product of 7 and 8
Sveta_85 [38]

Answer:

The result of multiplying 7 with 8 is called the product. Thus, the product of 7 and 8 is as follows:

56

In other words, we find the product of 7 and 8 by simply calculating 7 times 8 which equals 56. Pretty easy huh?

If someone asks you, "What is the product of 7 and 8?", your answer will be:

7 x 8 = 56

To find any product in the future on your own, just remember that the product is the answer you get when you multiply numbers together.

3 0
3 years ago
Read 2 more answers
The line perpendicular to y= (-3/2)x -4 and goes through (1,4)
Paladinen [302]

Answer <u>(assuming it is allowed to be in point-slope format)</u>:

y-4 = \frac{2}{3}(x-1)

Step-by-step explanation:

1) First, determine the slope. We know it has to be perpendicular to the given equation, y = -\frac{3}{2} x-4. That equation is already in slope-intercept form, or y = mx + b format, in which m represents the slope. Since -\frac{3}{2} is in place of the m in the equation, that must be the slope of the given line.

Slopes that are perpendicular are opposite reciprocals of each other (they have different signs, and the denominators and numerators switch places). Thus, the slope of the new line must be \frac{2}{3}.  

2) Now, use the point-slope formula, y-y_1 = m (x-x_1) to write the new equation with the given information. Substitute m, x_1, and y_1 for real values.

The m represents the slope, so substitute \frac{2}{3} in its place. The x_1 and y_1 represent the x and y values of a point the line intersects. Since the point crosses (1,4), substitute 1 for x_1 and 4 for y_1. This gives the following equation and answer:

y-4 = \frac{2}{3}(x-1)

3 0
3 years ago
Point A is located at (−2, 2), and point M is located at (1, 0). If point M is the midpoint of segment AB, find the location of
Lena [83]

sub B = (x,y)

midpoint= ( (x-2)/2, (y+2)/2 )

(x-2)/2=1 and (y+2)/2=0

x-2=2 and y+2=0

x=4 and y= -2

B= (4,-2)

5 0
3 years ago
Evaluate the Riemann sum for f(x) = 3x − 1, −6 ≤ x ≤ 4, with five subintervals, taking the sample points to be right endpoints.
Verdich [7]

Answer:

The Riemann sum equals -10.

Step-by-step explanation:

The right Riemann Sum uses the right endpoints of a sub-interval:

\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_1)+f(x_2)+f(x_3)+...+f(x_{n-1})+f(x_{n})\right)

where

\Delta{x}=\frac{b-a}{n}

To find the Riemann sum for \int\limits^{4}_{-6} {3x-1} \, dx with n = 5 rectangles, using right endpoints you must:

We know that a = -6, b = 4 and n = 5, so

\Delta{x}=\frac{4-\left(-6\right)}{5}=2

We need to divide the interval −6 ≤ x ≤ 4 into n = 5 sub-intervals of length \Delta{x}=2

a=\left[-6, -4\right], \left[-4, -2\right], \left[-2, 0\right], \left[0, 2\right], \left[2, 4\right]=b

Now, we just evaluate the function at the right endpoints:

f\left(x_{1}\right)=f\left(-4\right)=-13=-13

f\left(x_{2}\right)=f\left(-2\right)=-7=-7

f\left(x_{3}\right)=f\left(0\right)=-1=-1

f\left(x_{4}\right)=f\left(2\right)=5=5

f\left(x_{5}\right)=f(b)=f\left(4\right)=11=11

Finally, just sum up the above values and multiply by 2

2(-13-7-1+5+11)=-10

The Riemann sum equals -10

5 0
4 years ago
Please help me i don’t understand
Usimov [2.4K]
Well 2÷1/2 is 4 and 4×3/4 is 12/4 which is also 3 whloes
6 0
3 years ago
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