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Yakvenalex [24]
3 years ago
6

Solve the simultaneous equation:

12\\2x-3y=30" alt="4x+3y=-12\\2x-3y=30" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Shtirlitz [24]3 years ago
7 0

Answer:

(3, - 8 )

Step-by-step explanation:

4x + 3y = - 12 → (1)

2x - 3y = 30 → (2)

Add (1) and (2) term by term to eliminate y

6x + 0 = 18

6x = 18 ( divide both sides by 6 )

x = 3

Substitute x = 3 into either of the 2 equations and solve for y

Substituting into (1)

4(3) + 3y = - 12

12 + 3y = - 12 ( subtract 12 from both sides )

3y = - 24 ( divide both sides by 3 )

y = - 8

solution is (3, - 8 )

Darina [25.2K]3 years ago
6 0
<h3>Steps:</h3>

4x+3y=-12\\2x-3y=30

---------------------------

6x+0y=18

<em>This is the answer you just have to follow the integer rule and combine like variables that all!</em>

<u>please inform me if its wrong</u>

if this was helpful mark brainliest

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4 years ago
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5 0
3 years ago
A packet of crips weighs 32 grams to the nearest gram. A multipack of crisps contain 10 packets. work out the least and greatest
Sergeeva-Olga [200]

Answer:

The least and the greatest weights are 315 grams and 325 grams

Step-by-step explanation:

* Lets explain what is the upper and lower bounds

- The lower bound is the smallest value that would round up to the

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- The upper bound is the smallest value that would round up to the next

 estimated value.

- Ex: a mass of 70 kg, rounded to the nearest 10 kg, has a lower

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- So to understand how to find them divide the nearest value by 2

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∵ The approximated value is 32

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- To find the upper bound add 0.5 from the approximated value

∵ The approximated value is 32

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∵ The least value of one packet is 31.5

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∵ The greatest value of one packet is 32.5

∴ The greatest weight of the mulipack = 32.5 × 10 = 325 grams

∴ 315 ≤ weight of multipack < 325

* The least and the greatest weights are 315 grams and 325 grams

6 0
3 years ago
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