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3 years ago

The answers are 1/25 1/5 1/4 1/3

Mathematics

2 answers:

Fed [463]3 years ago

8 0

You put the answer there?? lol

Masja [62]3 years ago

6 0

Answer:

Why did you put the answer there??

Step-by-step explanation:

You might be interested in

Which quadratic function has Vertex (-1,4) and passes through (4,19) <br> HELP

hichkok12 [17]

Answer:

$f(x)=\frac{3}{5}(x+1)^2+4$

Step-by-step explanation:

The equation of a quadratic function in vertex form is given by:

$f(x)=a(x-h)^2+k$

Where (h,k) is the vertex.

It was given in the question that the vertex of the parabola is (-1,4).

When we substitute the vertex into the formula we get:

$f(x)=a(x+1)^2+4$

The parabola also passes through (4,19) hence it must satisfy its equation.

$19=a(4+1)^2+4$

$19-4=a(5)^2$

$15=25a$

We divide both sides by 25 to get:

$a=\frac{15}{25}= \frac{3}{5}$

Hence the quadratic function is:

$f(x)=\frac{3}{5}(x+1)^2+4$

6 0

3 years ago

Plz help its due TOMMOROW

sashaice [31]

Answer:

86%

Step-by-step explanation:

Let g represent the mean mark for the 10 girls in the class. Then the mean mark for the class was ...

10g +20(62%) = 30(70%)

g = 3(.7) -2(.62) . . . . . . . . . divide by 10 and subtract 2(.62)

g = .86 = 86%

The mean mark for girls was 86%.

_____

You can do this in your head if you consider it in terms of deviations from the mean. The second equation above can be rewritten and factored as ...

g = 70% +2(70% -62%)

That is, because there are 2 boys for every girl, the girl's score is above the mean by an amount that is 2 times the amount that the boy's score is below the mean. The boys' score is below by 8%, so the girls' score is above by 16%, so is 86%.

4 0

3 years ago

The equation 3x + 2 = 29 is modeled below.

DanielleElmas [232]

Answer:

Subtract 2 from both sides.

Step-by-step explanation:

Remember to do the opposite of PEMDAS. PEMDAS is the order of operation, and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

> Also, note the equal sign, what you do to one side, you do to the other side of the equation.

First step is to subtract 2 from both sides of the equation:

3x + 2 (-2) = 29 (-2)

3x = 29 - 2

3x = 27

The second step is to divide 3 from both sides of the equation:

(3x)/3 = (27)/3

x = 27/3

x = 9

7 0

2 years ago

Read 2 more answers

On the line you created from part A, mark a point D that is distinct from point C. Then, use the slope formula along with the co

ad-work [718]

The slope of AB and the slope of DC based on the information about the coordinate will be -2 and -2 respectively.

<h3>How to illustrate the information?</h3>

From the information given, we are told to use the slope formula along with the coordinates of points A, B, C, and D to find the slope.

The slope of AB based on the information will be:

= (-1 -3)/(-1 --3)

= -4/2

= 2

The slope of DC will be:

= 2-6/(1 --1)

= -4/2

= -2

Therefore, the slope of AB and the slope of DC based on the information about the coordinate will be -2 and -2 respectively.

Learn more about coordinate on:

brainly.com/question/11337174

#SPJ1

7 0

1 year ago

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$