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Nataly_w [17]
3 years ago
11

Plz help 100 points!!!!!!!!!!!!!!!!

Mathematics
2 answers:
enot [183]3 years ago
8 0

Answer:

I'm pretty sure is number two

Step-by-step explanation:

because I solved the problems

lara31 [8.8K]3 years ago
6 0

Answer:

The answer is A

Step-by-step explanation:

Express the number in scientific notation as real numbers:

9.4 \times  {10}^{ - 8}  = 0.000000094 \\ 9.25 \times  {10}^{ - 6}  = 0.00000925 \\ 2.5 \times  {10}^{3}  = 2500 \\ 7 \times  {10}^{3}  = 7000

So, from least to greatest;

0.000000094 - 0.00000925 - 2500 - 7000

9.4 x 10^-8, 9.25 x 10^-6, 2.5 x 10^3, 7 x 10^3 (first option)

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Five times the sum of a number and 27 is greater than or equal to six times the sum of that
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The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

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