If a spring stretches 6 meters when a 7-kilogram weight is attached to it, how much will it stretch when a 42-kilogram weight is
 attached to it?
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
Answer:
Step-by-step explanation:
  This is a simple proportion problems.
7 kilogram weight attache to a spring stretches  = 6 meters
  1 kilogram would stretch                                       =  6/7 m
Therefore 42 kilograms would  stretch                  = (6/7 x 42)meters
                                                                                  =  36 meters.
                                                                           
   
 
                                
             
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Answer:
41
Step-by-step explanation:
yellow marbles=5+ 3r(r is the number of red marbles)
red marbles=3r
3r+3r+5=77
6r=77-5
6r=72
r=72/6=12
yellow marbles = 5 + 3r
5+ 12 x 3
5+ 36
=41
 
        
             
        
        
        
Answer:
-3x+16
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
Mean = 70,000 dollars
SD = 800 dollars
For Khan Academy 
Step-by-step explanation:
 
        
             
        
        
        
Answer:
 The slope of the line passing through the points (5, -5) and (7,3) is 4 . Use the slope formula to find the slope.
 
        
             
        
        
        
Answer:
<h2>b = <u>2A</u></h2><h2>       h</h2><h2 />
Step-by-step explanation:
A = 1/2 b h
A2 = b h
b = <u>2A</u>
       h