If a spring stretches 6 meters when a 7-kilogram weight is attached to it, how much will it stretch when a 42-kilogram weight is
attached to it?
1 answer:
Answer:
Step-by-step explanation:
This is a simple proportion problems.
7 kilogram weight attache to a spring stretches = 6 meters
1 kilogram would stretch = 6/7 m
Therefore 42 kilograms would stretch = (6/7 x 42)meters
= 36 meters.
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41
Step-by-step explanation:
yellow marbles=5+ 3r(r is the number of red marbles)
red marbles=3r
3r+3r+5=77
6r=77-5
6r=72
r=72/6=12
yellow marbles = 5 + 3r
5+ 12 x 3
5+ 36
=41
Answer:
-3x+16
Step-by-step explanation:
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Mean = 70,000 dollars
SD = 800 dollars
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Step-by-step explanation:
Answer:
The slope of the line passing through the points (5, -5) and (7,3) is 4 . Use the slope formula to find the slope.
Answer:
<h2>b = <u>2A</u></h2><h2> h</h2><h2 />
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