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rodikova [14]
3 years ago
5

If a spring stretches 6 meters when a 7-kilogram weight is attached to it, how much will it stretch when a 42-kilogram weight is

attached to it?
Mathematics
1 answer:
Zinaida [17]3 years ago
8 0

Answer:

Step-by-step explanation:

 This is a simple proportion problems.

7 kilogram weight attache to a spring stretches  = 6 meters

 1 kilogram would stretch                                       =  6/7 m

Therefore 42 kilograms would  stretch                  = (6/7 x 42)meters

                                                                                 =  36 meters.

                                                                         

 

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It takes 300 newtons of force and a distance of 20 meters for a moving car to come to stop. How much work is a one n the cart?
IceJOKER [234]
Work done on cart
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W
=
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J
Kinetic energy of cart
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Explanation:
Work done
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and distance
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⇒
W
=
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Let's substitute the values of
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N

⋅
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⋅

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2

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⇒
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=
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kg

⋅

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2

s
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If f(x)=3x and g(x)=1/x, what is the domain of (g o f)(x)?
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