Answer:
y=4x+7
Step-by-step explanation:
4x+y=7
Isolate one of the variables
4x-4x+y=7+4x
y=7+4x
slope is 4 (Up 4, Right 1)
y-intercept is (0,7)
Answer:
(y - i
)(y + i
)
Step-by-step explanation:
Factor as a difference of squares, that is
y² + 7
= y² - (i
)²
= (y - i
)(y + i
)
I think you meant to say the equation is
y = 2x² - 2x + 3
Differentiate both sides with respect to x :
dy/dx = 4x - 2
At the point (3, 0), the slope of the tangent line is dy/dx(3) = 4•3 - 2 = 10. Then the normal line to the curve at (3, 0) has slope -1/10.
Using the point-slope formula, the equation of the normal line is
y - 0 = -1/10 (x - 3) ⇒ y = (3 - x)/10
The awnser is c (p6+q) +8