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(Quick please ) !!!!!!!!!!!!!!!! Help me!!!!! find the surface area of the rectangular prism!!!!!! thank you

Aleks [24]

You can do this !

The rectangular prism has

   -- length = 10 cm
   -- width = 7 cm
   -- height = 3 cm.

-- The area of the top and bottom is (length x width) each.

-- The area of the left and right sides is (length x height) each.

-- The area of the front and back is (width x height) each.

There. I just laid out all the schmartz you need to answer this question.
The rest is all simple arithmetic, and you're perfectly capable of turning
the crank and getting the answer. You don't need anybody else to do
that part for you.

Don't forget your units. The area of each flat face is (cm) times (cm),
and that product will be some cm² , for area.

3 0

3 years ago

The pyramid of khagra,in Egypt,is 488 feet tall. The Eiffel Tower,in France,is 1,063 feet tall. How much taller is the Eiffel To

steposvetlana [31]

Answer:

The Eiffel Tower in France is 575 feet taller than pyramid of khagra.

Step-by-step explanation:

We are given the following in the question:

Height of pyramid of khagra = 488 feet

Height of Eiffel Tower in France = 1,063 feet

Difference in height =

= Height of Eiffel Tower in France - Height of pyramid of khagra

$=1063 - 488\\= 575\text{ feet}$

Thus, the Eiffel Tower in France is 575 feet taller than pyramid of khagra.

7 0

3 years ago

Solve -8/5 x - 6 = -54

Musya8 [376]

The equation is false so no solution.

Simplify 8/5 * -6 to -48/5

Move the negative sign to the left

Simplify brackets

Since 48/5 = -54 its false so no answer

4 0

2 years ago

Read 2 more answers

What is the degree of 12x4 - 8x + 4x2 - 3? A. 8 B. 4 C. 3 D. 12

Soloha48 [4]

In this problem, we are asked to determine the degree of the given expression 12X4 - 8X + 4X2 -3. To answer this, first, we need to arrange the mathematical expression in descending order with respect to its power such as the new arrangement will become 12x4 + 4x2 -8x -3. The degree is clearly visible and it is 4. Therefore, the answer to this problem is the letter "B" which is 4.

4 0

3 years ago

Read 2 more answers

An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$

4 0

2 years ago