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deff fn [24]
9 months ago
11

Numbers the same _______ from _____ on a number line, but on the other side of zero. (Zero is its own opposite.)​

Mathematics
1 answer:
frutty [35]9 months ago
3 0

Answer:

Distance from zero

Step-by-step explanation:

I think this may be the answer with the information given.

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PLEASE ANSWER CORRECTLY! WILL GIVE BRAINLIEST!
vaieri [72.5K]

Answer:

0.7938

Step-by-step explanation:

z1 = (125-100)/15 = 1.667

P( < 125) = 0.9522

z2 = (85-100)/15 = -1

P( > 85) = 0.8413

0.9522 + 0.8413 - 1 = 0.7935

4 0
3 years ago
Which number line model represents the expression 3.5+(-5)
Anarel [89]

Answer:

D.

Step-by-step explanation:

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7 0
2 years ago
The image shows a ray of light bending at the boundary of a glass block. According to a law of optics, = n, where n is a constan
UkoKoshka [18]
The formula for the light bend would be n1*sin i= n2 * sin r

If you use "sin (90-x)= cos x" principle, you can change the sin in the equation into
n1*sin i= n2 * sin r
n1 * cos a= n2 * cos b
n2/n1= cos a/ cos b

Assuming the n constant is the ratio of the glass compared to water then the answer would be: cos a/ cos b
3 0
3 years ago
A girl has 98 beads, and all but 14 were lost. how many beads did she loose?<br>​
castortr0y [4]

Answer:

84 beads

Step-by-step explanation:

She had 98 beads and lost all but fourteen. So it would be 98 - 14 which would get you 84 beads that the girl has lost

8 0
3 years ago
Use the Parabola tool to graph the quadratic function. f(x)=2x^2−12x+19 Graph the parabola by first plotting its vertex and then
Debora [2.8K]
To find the vertex of our parabola, we are going to use the vertex formula: For a quadratic of the form f(x)=x^2+bx+c it vertex (h,k) is given by h= \frac{-b}{2a}, k=f(h).
We can infet from our parabola that a=2 and b=-12. So lets replace those values in our formula:
h= \frac{-b}{2a}
h= \frac{-(-12)}{2(2)}
h= \frac{12}{4}
h=3
k=f(h)=2(3)^2-12(3)+19
k=2(9)-36+19
k=18-17
k=1
The vertex (h,k) of our parabola is (3,1)

Now to find our second point, we are going to evaluate our parabola at x=0
f(0)=2(0)^2-12(0)+19
f(0)=0+0+19
f(0)=19
Our second point is (0,19)

We can conclude that we can graph the parabola f(x)=2x^2-12x+19 using its vertex (3,1) and the point (0,19) as follows: 

7 0
3 years ago
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